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3 years ago

Use the graph to determine the object’s average velocity.

Physics

1 answer:

Westkost [7]3 years ago

6 0

Answer: 0.1 m/s

Explanation:

m=1

s=10

1/10=0.1

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A triangular plate with height 6 ft and a base of 8 ft is submerged vertically in water so that the top is 4 ft below the surfac

solmaris [256]

Answer:

$F=4673.95lbs$

Explanation:

Recall weight density of water 62.5 lb/ft^3 and the height 6ft base 8ft

The width of the triangle

$\frac{W(x)}{7}=\frac{(8-x)}{2}$

The hydrostatic force is the pressure times area of the submerged

$W(x)=\frac{7*(8-x)}{4}$

$F=\int\limits {p} \, dA$

$F=\int\limits^8_2 {pgx*\frac{7}{4}*(8-x)} \, dx$

$F=\int\limits^8_2 {62.5*\frac{7}{4}*x*(8-x)} \, dx$

$F=109.375\int\limits^8_4{(8x-x^2)} \, dx$

$F=109.375[4x^2-\frac{1}{3}x^3]|4,8$

$F=109.375*42.73=4673.95lbs$

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4 years ago

A girl coasts down a hill on a sled, reaching level ground at the bottom with a speed of 7.1 m/s. The coefficient of kinetic fri

Lelu [443]

Answer:

114.19186 m

Explanation:

v = Velocity of girl at bottom = 7.1 m/s

$\mu$ = Coefficient of kinetic friction = 0.045

g = Acceleration due to gravity = 9.81 m/s²

d = Distance

N = Normal force = 783 N

The weight of the sled and girl is considered as the sum of the frictional force and weight

Hence we use the following equation where the kinetic energy and potential energy are conserved

$\frac{1}{2}mv^2=\mu Nd\\\Rightarrow \frac{1}{2}\frac{783}{9.81}\times 7.1^2=0.045\times 783\times d\\\Rightarrow d=\frac{1}{2}\times \frac{783\times 7.1^2}{9.81\times 0.045\times 783}\\\Rightarrow d=114.19186\ m$

The sled travels 114.19186 m on the level ground before coming to a rest

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3 years ago

Which of the following is true regarding the speed of earthquake waves?

Levart [38]

Answer:

p waves travel faster than s waves and surface waves

4 0

3 years ago

A ball has a diameter of 3.77 cm and average density of 0.0839 g/cm3. What force is required to hold it completely submerged und

mestny [16]

Answer:

0.25 N

Explanation:

The density of the ball ( $\rho_b$ ) = 0.0839 g/cm³ = 83.9 kg/m³

The density of water ( $\rho_w$ ) = 1000 kg/m³

diameter = 3.77 cm = 0.0377 m

radius of ball = 0.0377/2 = 0.01885 m

The volume (V) = $\frac{4}{3} \pi r^3=\frac{4}{3}*\pi*0.01885^3=2.8*10^{-5}\ m^3$

Let us assume the acceleration due to gravity (g) = 9.8 m/s²

Hence:

The force is required to hold it completely submerged under water (F) is:

$F=\rho_w Vg-\rho_b Vg=1000*(2.8*10^{-5})*9.81-83.9*(2.8*10^{-5})*9.81\\\\$

F = 0.25 N

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3 years ago

Read the excerpt from "Introduction to Poetry" by Billy Collins. or walk inside the poem's room and feel the walls for a light s

faust18 [17]

Answer:

Explanation:

Well someone has to understand the Poet Lol.

:) hope i helped

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3 years ago

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