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4 years ago

In a science experiment, a variable is:

Chemistry

1 answer:

rewona [7]4 years ago

3 0

A variable is any factor,trait, or condition that can exist in differing amounts or types.

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There is a close relation between forest<br>and wildlife.

evablogger [386]

Answer:

habitat

Explanation:

wild animal need

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3 years ago

If an element has two or more atoms with the same number of protons but different number of neutrons it is called what

Oksana_A [137]

It’s called an isotope which is an atom with the same number of protons but a different number of neutrons

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3 years ago

How does Controlled fires help prevent real forest fires?

Salsk061 [2.6K]

Answer:

it burns things which would be burned easily by lightning, and then people put the fire out immediately. If the dried plants that they are lighting on fire are hit by lightning, it can lead to a massive fire without anyone realizing.

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3 years ago

A piece of metal with a mass of 611 g is placed into a graduated cylinder that contains 25.1 ml of water, raising the water leve

jeka94

Mass of metal piece is 611 g and volume of graduated cylinder is 25.1 mL. When metal piece is placed in the graduated cylinder water level increases to 56.7 mL. The increase in volume is due to volume of metal piece that gets added to the volume of water.

Thus, volume of metal piece can be calculated by subtracting initial volume from the final one.

$V_{metal}=V_{final}-V_{initial}=(56.7-25.1)mL=31.6 mL$

Thus, volume of metal piece will be 31.6 mL. The mass of metal piece is given 611 g, density of metal can be calculated as follows:

$d=\frac{m}{V}=\frac{611 g}{31.6 mL}=19.33 g/mL$

Therefore, density of metal is 19.33 g/mL.

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4 years ago

If 36.2g of Acetic Acid (HC2H302) was dissolved in 300. mL of water, what is the

uysha [10]

Answer:

2.01 M

Explanation:

Step 1: Calculate the moles of acetic acid (HC₂H₃O₂)

The molar mass of acetic acid is 60.05 g/mol. We will use this data to calculate the moles corresponding to 36.2 g of acetic acid.

$36.2g \times \frac{1mol}{60.05g} = 0.603mol$

Step 2: Convert the volume of solution to liters

We will use the relation 1000 mL = 1 L. We assume that the volume of solution is that of water (300 mL)

$300mL \times \frac{1L}{1000mL} = 0.300L$

Step 3: Calculate the molarity of the solution

The molarity is equal to the moles of solute (acetic acid) divided by the liters of solution

$M = \frac{0.603mol}{0.300L} = 2.01 M$

7 0

3 years ago