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4 years ago

15

If a hot air balloon has an initial volume of 1000 L at 50 ∘C, what is the temperature (in ∘C) of the air inside the balloon if

the volume expands to 1700 L ?

1 answer:

puteri [66]4 years ago

3 0

<span>(P1/T1) = (P2/T2)

T must be in kelvin first!</span>

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HELP PLEASE!!!!!!!

ololo11 [35]

Answer:

Try a grams calculator, Its pretty to nd one :D

Explanation:

8 0

3 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

3 years ago

An ecologist notices that an important coral reef is dying off. He believes that it has to do with some pollution from a local e

Rzqust [24]

A hydrologist should analyze the water for contamination

6 0

1 year ago

A lead ball is added to a graduated cylinder containing 30.8 ml of water, causing the level of the water to increase to 89.9 ml.

enot [183]

A lead ball added to a graduated cylinder containing 30.8 ml of water, causing the level of the water to increase to 89.9 ml, has a volume of 59.1 ml.

Volume is defined as the amount of space that matter occupies. There are three different ways to find the volume:

1) Volume by Space - by measuring its physical dimensions

2) Volume by Density and Mass - by dividing its weight by its density

3) Volume by Displacement - by measuring the volume displaced when immersed in a liquid or gas

To solve for the volume of the lead ball, we can use the displacement method by subtracting the initial volume from the final volume.

If the level of the water increased from 30.8 ml to 89.9 ml upon adding the lead ball, the displaced volume is:

volume = final volume - initial volume

volume = 89.9 - 30.8

volume = 59.1 ml

Hence, the volume of the lead ball, using displacement method, is 59.1 ml.

To learn more about volume by displacement: brainly.com/question/1945909

#SPJ4

3 0

2 years ago

Which is an example of kinetic energy?

umka2103 [35]

C) electrical energy

7 0

3 years ago