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sergey [27]
3 years ago
5

HELP ME ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
valkas [14]3 years ago
5 0
C the atmosphere provides warmth
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30 points 2 questions HELP!!
salantis [7]

Answer:

Generally with successive half-life a new element is formed from the decayed nuclei:

isotope - daughter nucleus has same no. of protons (same atomic number) so                       the same element is formed in the decay

isotone - daughter nucleus has same number of neutrons so the atomic number has changed and a new element is formed (new atomic number)

isobar - daughter nucleus has same mass number - this could be an example of beta decay where the decayed nucleus has the same mass number but loses a neutron and gains a proton because of the lost electron and a new element is formed with the atomic number increases by 1

Example:

    U238 Uranium - alpha to Th234

    Th234 Thorium - 2 beta to U234     (back to U but atomic mass less by 4)

   U234 Uranium - alpha to Th230

   Th230 Thorium - alpha to Ra226

etc.   but during beta decay (electron loss) a neutron is lost and a proton gained (answer a)

3 0
3 years ago
Force due to gravity. While JWST is in orbit, the Earth will be at a distance of 1.494 x 109 m from the telescope, and the Sun w
Alona [7]

Answer:

the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

Explanation:

Given that;

distance of earth from the telescope r1 = 1.494 × 10⁹ m

and the Sun will be 1.49598 × 10¹¹ m further away

so r2 = r1 + 1.49598 × 10¹¹

r2 = 1.494 × 10⁹ m + 1.49598 × 10¹¹ m = 1.51092 × 10¹¹ m

mass of sun Ms = 1.9884 × 10³⁰ kg

mass of earth Me = 5.945× 10²⁴ kg

mass of JWST Mj = 6500 kg

What is the gravitational force JWST will feel from the Sun (strength and direction)?

the gravitational force of the sun will be attractive based on Newton law of gravitational force; so

Fjs = GMjMs / r2²

constant G = 6.674 × 10⁻¹¹ Nm²/kg²

Force on the JWST by the sun will be;

Fjs = GMjMs / r2² { leftward}

we substitute

Fjs = [(6.674 × 10⁻¹¹ Nm²/kg²)(6500 kg )(1.9884 × 10³⁰ kg)] / (1.51092 × 10¹¹ m)²

=  (8.62587804 × 10²³) / ( 2.28287925 × 10²² )

= 37.785 Newton { leftward }

Therefore, the gravitational force JWST will feel from the Sun is 37.785 Newton { leftward }

7 0
3 years ago
1 jWhat is the correct unit for temperature? <br>​
Nadya [2.5K]

Answer:

Answer: Kelvin ________________

8 0
3 years ago
What can one say for sure about element #99, Einsteinium (Es))? a) There's no such element! b) It is an alkali metal. c) It is r
Dmitrij [34]

Answer:

Option (C)

Explanation:

Einsteinium is an element of the periodic table grouped in the Actinide series, with atomic number 99. They are dense element and highly electro-positive. <u>They are highly radioactive</u>, i.e the atoms within the element are unstable and constantly decay until they reach a stable environment. It has 99 number of electrons and protons, 153 number of neutrons.

Due to its high radioactivity, they are health hazardous and can used in making nuclear weapons but their uses are very limited and unknown.

Thus, the correct answer is option (C).

8 0
4 years ago
What is the mass number of a<br>neon isotope that has 9<br>neutrons? *<br><br>​
Luda [366]

Neon is element #10, so every neon atom has 10 protons in the nucleus.

If it also has 9 neutrons in there, then its mass number is (10 + 9) = <em>19</em> .

7 0
3 years ago
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