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jek_recluse [69]
2 years ago
11

What is ohms law PLEASE ANSWER THIS I NEED IT FAST ​

Physics
1 answer:
Lorico [155]2 years ago
6 0

Answer:

Ohms law states that current is directly proportional to the potential difference across the ends of a conductor provided that temperature and other factors kept constant

V=I(R)

You might be interested in
If a car accelerates from rest at a constant 4 m/s
Readme [11.4K]

Answer:

The time it will take for the car to reach a velocity of 28 m/s is 7 seconds

Explanation:

The parameters of the car are;

The acceleration of the car, a = 4 m/s²

The final velocity of the car, v = 28 m/s

The initial velocity of the car, u = 0 m/s (The car starts from rest)

The kinematic equation that can be used for finding (the time) how long it will take for the car to reach a velocity of 28 m/s is given as follows;

v = u + a·t

Where;

v = The final velocity of the car, v = 28 m/s

u = The initial velocity of the car = 0 m/s

a = The acceleration of the car = 4 m/s²

t = =The time it will take for the car to reach a velocity of 28 m/s

Therefore, we get;

t = (v - u)/a

t = (28 m/s - 0 m/s)/(4 m/s²) = 7 s

The time it will take for the car to reach a velocity of 28 m/s, t = 7 seconds.

4 0
2 years ago
Factors that affect acceleration due to gravity.<br>​
hram777 [196]

Answer

Factors Affecting Acceleration Due to Gravity

 

(1) Position on the planetary surface, it is higher at the axis (poles),

(2) Mass of the planet, higher with planets of larger masses

(3) Distance between object and the centre of planet, the larger the distance, the smaller the acceleration due to gravity.

Mark me as Brainlist if this answer is helpful for you

8 0
2 years ago
Read 2 more answers
Can i get the answer quickly plz
max2010maxim [7]
Sure you can..... ....................
5 0
2 years ago
Which character trait below is a trait that both Michael Faraday and Nikola Tesla had?
-Dominant- [34]
They were both odd and obsessive
7 0
3 years ago
A student holds one end of a thread, which is wrapped around a cylindrical spool, as shown above. The student then drops the spo
lesya [120]

by energy conservation we know that

KE or rotation + KE of translation = gravitational PE

now we have

\frac{1}{2}I\omega^2 + \frac{1}{2}mv^2 = mgH

also we know that

v = R\omega

now we have

\frac{1}{2}(\frac{1}{2}mR^2)\omega^2 + \frac{1}{2}m(R\omega)^2 = mgH

\frac{3}{4}mR^2\omega^2 = mgH

\omega = \sqrt{\frac{4gH}{3}}/R

now when it is rolling on ground the torque acting on it due to friction force is given by

\tau = R F_f

\tau = \mu mg R

\alpha = \frac{\mu mg R}{\frac{1}{2}mR^2}

\alpha = \frac{2 \mu g}{R}

now angular speed at any time is given as

\omega = \omega_i + \alpha t

\omega = \sqrt{\frac{4gH}{3}}/R -\frac{2 \mu g}{R} t

so above is the angular speed in terms of time "t"

7 0
3 years ago
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