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1 year ago

If an incident light ray hits a flat smooth object at 28 degrees, it will reflect off at an angle of…

1 answer:

Nookie1986 [14]1 year ago

5 0

Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.

Hence, option B is correct

To learn more about the law of reflection, refer to the link;

brainly.com/question/12029226

#SPJ1

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What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?

Salsk061 [2.6K]

Answer:

1.48kg

Explanation:

Here,

potential energy (P.E) = 29j

height (h) = 2m

acceleration due to gravity(g) =

$9.8m {s}^{ - 2}$

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1 year ago

A 235 kg motorcycle moves with a velocity of 7 m/s. What's it's kenetic energy?

antiseptic1488 [7]

The non-relativistic formula for low speed v < 0.1c is:

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3 years ago

Suppose the electric field in some region is found to be E = kr3 ˆr, in spherical coordinates (k is some constant). (a) Find the

Assoli18 [71]

Answer:

Part a)

$\rho = 3\epsilon_0 k r^2$

Part b)

$Q = 4\pi \epsilon_0kR^5$

Explanation:

Part a)

As we know that electric field intensity due to some given charge distribution is given as

$E = kr^3 \hat r$

now electric flux through a spherical surface of radius r is given as

$\phi = E. A$

$\phi = kr^3(4\pi r^2)$

now by Guass law we know that

$E.A = \frac{q}{\epsilon_0}$

$q = 4\pi \epsilon_0kr^5$

now volume charge density is given as

$\rho = \frac{q}{\frac{4}{3}\pi r^3}$

$\rho = 3\epsilon_0 k r^2$

Part b)

Total charge inside the radius R is given as

$Q = 4\pi \epsilon_0kR^5$

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2 years ago

How is it possible for a person watching a baseball game on TV to hear sounds before someone who is actually watching the same g

Andreyy89

Answer:

It is possible because, the TV broadcast audio and video signals in radio frequency which travels at the speed of light while the audio signals travel to those present in the stadium at the speed of sound which is over eight hundred thousand times slower than the speed of light

Explanation:

It is possible because of the following;

1. TV signals from the camera (including the captured sound) very close to the field of play are transmitted through the radio frequency bands and as such are a form of electromagnetic radiation that travels at the speed of light which is about 300,000 km/second

It will therefore, take 1 second for a sound of the game to reach someone located at 300,000,000 meters watching a live televised game

2. The speed of sound is about 343 m/second and it therefore takes up to 2 seconds for a sound to reach someone 686 meters away from the ball in the stadium.

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3 years ago

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Vilka [71]

Because the sound waves are being observed by the people that are there and it is not empty as in an empty place the sound waves will come back to you.

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3 years ago