The coin's acceleration is <u>0.37 m/s²</u>
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
<u>Calculation:-</u>
<u />
V² = U -2aS
a = U/2S
= 2/2×2.7
= <u>0.37 m/s²</u>
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
Learn more about acceleration here:- brainly.com/question/29110429
#SPJ9
If the field is in a vacuum, the magnetic field is the dominant factor determining the motion. Since the magnetic force is perpendicular to the direction of travel, a charged particle follows a curved path in a magnetic field. The particle continues to follow this curved path until it forms a complete circle. Another way to look at this is that the magnetic force is always perpendicular to velocity, so that it does no work on the charged particle. The particle’s kinetic energy and speed thus remain constant. The direction of motion is affected but not the speed.
A negatively charged particle moves in the plane of the paper in a region where the magnetic field is perpendicular to the paper (represented by the small × ’s—like the tails of arrows). The magnetic force is perpendicular to the velocity, so velocity changes in direction but not magnitude. The result is uniform circular motion.
According to KE = (3/2)kT
reducing temperature, in KELVIN, by half, average KE is reduced by half.
Answer:
Since the bar cannot translate, linear momentum is not conserved
Explanation:
By conservation of the angular momentum:
Lo = Lf
where
; 
; d=1.6m; L=3m; 
; 
; 
Solving for 
:
Replacing the values we get:
Since the bar can only rotate (it canno translate), only angular momentum is conserved.
