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Nataliya [291]
3 years ago
13

A person is nearsighted with a far point of 75.0 cm. a. What focal length contact lens is needed to give him normal vision

Physics
1 answer:
BigorU [14]3 years ago
7 0

Complete Question

The  complete question is  shown on the first uploaded image  

Answer:

a

  f=  -75 \ cm =  - 0.75 \ m

b

  P  =  -1.33 \ diopters

Explanation:

From the question we are told that

    The  image distance is  d_i =  -75 cm

The value of the image is negative because it is on the same side with the corrective glasses

    The  object distance is  d_o =  \infty

The  reason object distance  is because the object father than it being picture by the eye

General focal length is mathematically represented as

              \frac{1}{f}  =  \frac{1}{d_i}  -   \frac{1}{d_o}

substituting values

             \frac{1}{f}  =  \frac{1}{-75}  -   \frac{1}{\infty}

=>         f=  -75 \ cm =  - 0.75 \ m

Generally the power of the corrective lens is  mathematically represented as

        P  =  \frac{1}{f}

substituting values

       P  =  \frac{1}{-0.75}

        P  =  -1.33 \ diopters

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One car has two and a half times the mass of a second car, but only half as much kinetic energy. When both cars increase their s
Leokris [45]

Answer:

v_1 = 7.96 m/s

v_2 = 17.8 m/s

Explanation:

Let the mass of the other car is "m" and its kinetic energy is

K = \frac{1}{2}mv^2

now the mass of the first car is two and half times and its kinetic energy is half that of other car

so we will have

\frac{1}{2}(2.5m)v_1^2 = \frac{1}{2}(\frac{1}{2}mv^2)

2.5 v_1^2 = 0.5 v^2

v_1 = 0.447 v

now speed of both cars is increased by value of 9 m/s

so now we will have same kinetic energy for both cars

\frac{1}{2}(2.5 m)(0.447v + 9)^2 = \frac{1}{2}m(v + 9)^2

2.5(0.447 v + 9)^2 = (v + 9)^2

1.58(0.447v + 9) = v + 9

0.293v = 5.22

v = 17.8 m/s

so speed of first car is

v_1 = 0.447 v = 7.96 m/s

v_2 = 17.8 m/s

3 0
3 years ago
You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
umka21 [38]

Answer:

The funda mental frequency of the original tube is 182Hz.

Explanation:

See the attachment for the calculation steps.

In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.

For closed tubes

f = nv/4L (n = 1, 3, 5,...n)

f = nv/2L (n = 1, 2, 3,...n)

The details of calculation can be found below in the attachment.

4 0
3 years ago
Find the equivalent resistance Req between terminals a and b if terminals c and d are open and again if terminals c and d are sh
adoni [48]

Answer:

351 ohm

720 ohm

Explanation:

When c and d are open:

Terminals c and d are open.. If you  redraw the circuit as below, you can see that the two resistors in the first  column are in parallel as, they are connected together at both pairs of terminals  (due to the short).

Hence, we have a pair of parallel resistors:

Req1 = (R1*R2)/ (R1 + R2) = 360*540/(360+540) = 216 ohms

Req2 = (R3*R4)/ (R3 + R4) = 180*540/(180+540) = 135 ohms

Now these two sets are  in series with another Hence,

Req = Req1 + Req2 = 216 + 135 = 351 ohms

Answer: 351 ohms

When c and d are shorted:

The current will flow through the least resistant path naturally from resistors R3 and R1 or R4.

Both of these resistor lie in a single path placing the resistors in series to one another, hence

Req = R3 + R1 = 180 + 540 = 720 ohms

Answer:720 ohms

7 0
3 years ago
Why is gravity considered a force?
sattari [20]
Gravity is a force because it pulls down on objects.
5 0
3 years ago
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Which product of nuclear decay has mass but no charge?
Tom [10]
Neutrons have a zero charge but consist of mass.
3 0
2 years ago
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