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mote1985 [20]
3 years ago
10

Sec^6x(secxtanx)-sec^4(secxtanx)=sec^5xtan^3x Verify the trigonometric identity

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

I guess you mean

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan^3x

On the left side, we have a common factor of \sec^4x(\sec x\tan x)=\sec^5x\tan x, so that

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan x(\sec^2x-1)

Recall that

\sec^2x=1+\tan^2x

from which it follows that

\sec^5x\tan x(\sec^2x-1)=\sec^5x\tan x\tan^2x=\sec^5x\tan^3x

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