Answer:
c) The slope is not constant and increases with increasing time.
Explanation:
The equation for the position of this particle (starting from rest is)
![s = at^2/2 = 5t^2/2 = 2.5t^2](https://tex.z-dn.net/?f=s%20%3D%20at%5E2%2F2%20%3D%205t%5E2%2F2%20%3D%202.5t%5E2)
We can take derivative of this with respect to time t to get the equation of slope:
![s' = (2.5t^2)' = 2*2.5t = 5t](https://tex.z-dn.net/?f=s%27%20%3D%20%282.5t%5E2%29%27%20%3D%202%2A2.5t%20%3D%205t)
As time t increase, the slope would increases with time as well.
ANSWER:
3408.81 kg
STEP-BY-STEP EXPLANATION:
Given:
v = 111 m/s
Ek = 21000000 J
We have that the formula for kinetic energy is as follows:
![E_k=\frac{1}{2}\cdot m\cdot v^2](https://tex.z-dn.net/?f=E_k%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%5Ccdot%20v%5E2)
We substitute the values given in the exercise and solve for m (mass)
![\begin{gathered} 21000000=\frac{1}{2}\cdot m\cdot111^2 \\ m=\frac{21000000\cdot2}{111^2} \\ m=3408.81\text{ kg} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%2021000000%3D%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20m%5Ccdot111%5E2%20%5C%5C%20m%3D%5Cfrac%7B21000000%5Ccdot2%7D%7B111%5E2%7D%20%5C%5C%20m%3D3408.81%5Ctext%7B%20kg%7D%20%5Cend%7Bgathered%7D)
The mass of the helicopter is 3408.81 kilograms.
Answer:
Explanation:
Given,
initial angular speed, ω = 3,700 rev/min
=
final angular speed = 0 rad/s
Number of time it rotates= 46 times
angular displacement, θ = 2π x 46 = 92 π
Angular acceleration
![\alpha = \dfrac{\omega_f^2 - \omega^2}{2\theta}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cdfrac%7B%5Comega_f%5E2%20-%20%5Comega%5E2%7D%7B2%5Ctheta%7D)
![\alpha = \dfrac{0 - 387.27^2}{2\times 92\ pi}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cdfrac%7B0%20-%20387.27%5E2%7D%7B2%5Ctimes%2092%5C%20pi%7D)
![\alpha = -259.28 rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%20-259.28%20rad%2Fs%5E2)
Answer:
natural motion and violent motion
Explanation: