Because the polar regions receive low-angle insolation.
Insolation is the amount of solar radiation received by a given area. The Sun is always low on the horizon. The low Sun angle makes the beam of solar radiation to travel a longer distance from upper troposphere to reach earth's surface as compared to when it is directly overhead. In this case, the radiations are scattered and reflected more by the atmosphere and spread over a larger area. Thus, the intensity of solar radiation is very less at polar regions than near the equatorial region. This is the reason of very cold climates at polar regions.
5089 I believe is the correct answer
Answer:
The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.
Explanation:
To solve this problem we use the parabolic motion equations:
We define:
: total initial speed =
:initial speed component in vertical direction (y)
=
: vertical speed at any point on the parabolic path
g= acceleration of gravity= 9,8
= angle that forms the total initial velocity with the ground
Equation of the speed of the football in the vertical direction :
Equation (1)
We replace, in the equation (1):
Equation(2)
Angle calculation
The speed of the football in the vertical direction gradually decreases until its value is zero when it reaches the maximum height.
We replace , in the equation (2)
°
Answer:The football must be launched whit an angle of 20,487 degrees to reach a maximum height of 10 meters.
The answer that best fits the blank provided above is 30 KILOMETERS PER SECOND. The orbital speed of the Earth as recorded is 30 kilometers per second or <span>107000 km/h or</span> 18½ miles per second. The orbital period is 365 days which makes one year. Hope this helps.
Answer:
Ts=51.83C
Explanation:
First we calculate the surface area of the cylinder, neglecting the top and bottom covers as indicated by the question
Cilinder Area= A=πDL
L=200mm=0.2m
D=20mm=0.02m
A=π(0.02m)(0.2m)=0.012566m^2
we use the equation for heat transfer by convection
q=ha(Ts-T)
q= heat=2Kw=2000W
A=Area=0.012566m^2
Ts=surface temperature
T=water temperature=20C
Solving for ts
Ts=q/(ha)+T
Ts=2000/(5000*0.012566m^2)+20=51.83C