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3 years ago

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A cartridge electrical heater is shaped as a cylinder of length L = 200 mm and outer diameter D = 20 mm. Under normal operating

conditions the heater dissipates 2 kW while submerged in a water flow that is at 20°C and provides a convection heat transfer coefficient of h = 5000 W/m2 · K. Neglecting heat transfer from the ends of the heater, determine its surface temperature Ts. If the water flow is inadvertently terminated while the heater continues to operate, the ____

1 answer:

KengaRu [80]3 years ago

4 0

Answer:

Ts=51.83C

Explanation:

First we calculate the surface area of the cylinder, neglecting the top and bottom covers as indicated by the question

Cilinder Area= A=πDL

L=200mm=0.2m

D=20mm=0.02m

A=π(0.02m)(0.2m)=0.012566m^2

we use the equation for heat transfer by convection

q=ha(Ts-T)

q= heat=2Kw=2000W

A=Area=0.012566m^2

Ts=surface temperature

T=water temperature=20C

Solving for ts

Ts=q/(ha)+T

Ts=2000/(5000*0.012566m^2)+20=51.83C

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a) $k=19.6N/m$

b) $V_m=0.81m/s$

c) $a_m=6.561m/s^2$

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e) $T=0.78sec$ & $F=1.29sec$

f) $mx'' + kx' =0$

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From the question we are told that:

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Mass $m=0.30kg$

Total stretch length $L_t=0.150+0.100=>0.25$

a)

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$F=-km\\\\k=F/m\\\\k=\frac{m*g}{x}\\\\k=\frac{0.30*9.8}{0.15}$

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$V_m=A\omega$

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Generally the equation for Total mechanical energy of Mass on the spring is mathematically given by

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$F=\frac{1}{T}$

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Generally the Equation of time-dependent vertical position of the mass is mathematically given by

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