Answer:
The coefficient of static friction is : 0.36397
Explanation:
When we have a box on a ramp of angle 
, and the box is not sliding because of friction, one analyses the acting forces in a coordinate system system with an axis parallel to the incline.
In such system, the force of gravity acting down the incline is the product of the box's weight times the sine of the angle:
Recall as well that component of the box's weight that contributes to the Normal N (component perpendicular to the ramp) is given by:
and the force of static friction (f) is given as the static coefficient of friction (
) times the normal N:
When the box starts to move, we have that the force of static friction equals this component of the gravity force along the ramp:
Now we use this last equation to solve for the coefficient of static friction, recalling that the angle at which the box starts moving is 20 degrees:
Answer:
Move the opposite direction ( at a lesser magnitude of velocity)
Explanation:
Answer:1834.56 joules
Explanation:
Distance=36m
Coefficient of friction=0.2
Mass=26kg
Acceleration due to gravity=9.8m/s^2
Reaction=mass x acceleration due to gravity
Reaction=26 x 9.8
Reaction=254.8N
Coefficient of friction=frictional force ➗ reaction
0.2=frictional force ➗ 254.8
Frictional force=0.2 x 254.8
Frictional force=50.96N
work=friction force x distance
Work=50.96 x 36
Work=1834.56
Work=1834.56 joules
Answer:
Transverse wave
Explanation:
Its because in transverse wave the particle displacement is perpendicular to the direction of wave propagation..hope it helps you...
Answer: h = 0.30 m
Explanation:
A person jumping from height h would possess potential energy = m g h
which will convert completely into kinetic energy as person hits the ground. Now, the maximum energy absorbed by the person can be = 200 J
m = 67 kg
g = 9.8 m/s²
⇒ m g h = 200 J
⇒ h = 200 J / (67 kg × 9.8 m/s²) = 0.30 m
Hence, a person can land safely on both legs without breaking them from a height of 0.30 m only.
