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Dimas [21]
4 years ago
5

Give some everyday examples of the transport of heat by convection and by radiation.

Physics
1 answer:
Ksivusya [100]4 years ago
4 0

Answer and Explanation:

TRANSPORTATION OF HEAT THROUGH CONVECTION :

  • The best example of heat transfer from convection process is fan when there is too hot and we switch on the fan then the air which are produced by fan cools the room this process of removing heat is called connective heat transfer.
  • When milk is too hot and we want to drink it then we blow air across milk so that milk will become cool this is also a convection process.

TRANSPORTATION OF HEAT THROUGH RADIATION  :

  • The best example of heat transfer from radiation from radiation process is Sun from sun we got heat in form of radiation
  • When we go on the roof in night in winter days it is so cooled this is also due to radiation process.
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according to newton's law of universal gravitation, in which of the following situations does the gravitational attraction betwe
Alex17521 [72]

Explanation:

The force acting between two masses is given by :

F=G\dfrac{m_1m_2}{d^2}........(1)

Where

G is the universal gravitational constant

m_1\ and\ m_2 are masses

d is the distance between two masses

It is clear from equation (1) that the gravitational attraction between the bodies always increases if the masses of bodies increases and when the separation between masses decreases.

So, the correct answer is "the masses increase, and the distance between the centers of mass decreases". This is because the force of gravitation is directly proportional to the masses and inversely proportional to the separation.

4 0
3 years ago
A Gaussian surface in the form of a hemisphere of radius R = 5.51 cm lies in a uniform electric field of magnitude E = 1.08 N/C.
Ksju [112]

Answer:

Flux_{base}=-0.0103Nm^2/C

Flux_{curvePortion}=-Flux_{base}=0.0103Nm^2/C

Explanation:

a)At the base of the surface the Electric flux is easy to find, because the Electric Field is constant in magnitude and perpendicular to the flat surface:

Flux_{base}=-E*S=-E*\pi*R^2=-1.08*\pi*0.0551^2=-0.0103Nm^2/C

The Flux is negative because the Electric field goes into the surface

b) The Gaussian surface in form of a hemisphere encloses no net charge. The Gauss law says that the Flux of the electric field is proportional to the net charge enclosed. At this case, the charge is zero, then the total Flux is zero too.

Flux_{total}=Flux_{base}+Flux_{curvePortion}=0

Then:

Flux_{curvePortion}=-Flux_{base}=0.0103Nm^2/C

The Flux is positif because the Electric field goes out of the surface.

4 0
3 years ago
Photosynthesis transforms molecules of water and carbon dioxide into Molecules of?
brilliants [131]
Into molecules of sugar and oxygen.
The complete reaction of the photosynthesis is in fact:
6CO_2+6H_2O \rightarrow C_6H_{12}O_6+6O_2
and the energy of the light coming from the sun is also used to make the reaction possible.
7 0
4 years ago
A projectile is launched at ground level with an initial speed of 50.0 m/s at an angle of 30.0° above the horizontal. it strike
Anni [7]
<span>x = 129.9 m y = 30.9 m First, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m</span>
8 0
4 years ago
The internal energy of a system changes because the system gains 160 J of heat and performs 309 J of work. In returning to its i
o-na [289]

Answer:

w=255

Explanation:

The change in internal energy is given by the first law:

ΔE = Q - w

where ΔE is the change in internal energy of the system

q is the heat added to the system

w is the work done *by* the system on the surroundings

So, for the first phase of this process:

ΔE = Q - w

Q=160J

w=309J

ΔE = 160J - 309J = -149J

To bring the system back to its initial state after this, the internal energy must change by +149J (the system myst gain back the 149 J of energy it lost).  We are told that the system loses 106 J of heat in returning to its initial state, so the work involved is given by:

ΔE = Q - w

+149J = -106J - w

255J = -w

w = -255J

5 0
3 years ago
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