If two objects are repelled from each other which force most likely caused this?

PLEASE HELP. GRAVITY QUESTION, WRITTEN RESPONSE.

Rina8888 [55]

1) Forces acting on your body: force of gravity and normal reaction

2) Due to Newton's second law, N = mg

Explanation:

1)

When you sit on the computer, there are only two forces acting on you:

The force of gravity, acting downward, of magnitude $W=mg$ , where m is your mass and $g=9.8 m/s^2$ is the acceleration due to gravity, downward
The normal reaction exerted by the chair on you, $N$ , acting upward

Your body is in equilibrium (it doesn't move), this means that the two forces balance each other, therefore:

$N-mg=0\\N=mg$

2)

We can now apply Newton's second law of motion to this situation; this law states that the net force acting on a body is equal to the product between its mass and its acceleration. Mathematically,

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

In this situation, the net force is

$\sum F = N-mg$

So the equation becomes

$N-mg=ma$

However, we observe that your body is at rest; therefore, the acceleration is zero:

a = 0

And therefore,

$N-mg=0\\N=mg$

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4 0

4 years ago

Which part of an Adam is actively exchanged or shared in a chemical bond?

Lemur [1.5K]

Atom* the particles are (Electrons)

5 0

3 years ago

Which of the following models shows how unpredictable electrons are?

Fantom [35]

D

The exact location of electrons in electron shells of atoms cannot be exactly ascertained. This is why VSPER atomic models represent the position of electrons (s, p, d, & f) using the probability of where they would most be expected to be found.

Explanation:

This is because merely observing electrons changes their behavior. Remember that to observe something one has to shine light on it so it bounces back to the eye. Due to the negligible mass of electrons, mere photons of light will change their direction of movement, spin or other behaviors/properties.

Learn More:

For more on electron clouds check out;

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7 0

3 years ago

Read 2 more answers

A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway

Andru [333]

Answer:

63.44 rad/s

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet $v_{1}$ = 250 m/s

final velocity of bullet $v_{2}$ = 140 m/s

loss of kinetic energy of the bullet = $\frac{1}{2}m(v^{2} _{1} - v^{2} _{2})$

==> $\frac{1}{2}*0.0033*(250^{2} - 140^{2} )$ = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = $\frac{1}{2} mv^{2}$

70.785 = $\frac{1}{2}*0.25*v^{2}$

566.28 = $v^{2}$

$v= \sqrt{566.28}$ = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 = 63.44 rad/s

5 0

3 years ago

A 2.2 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.06 m, and the h

Veronika [31]

Answer:

$U=-22.85J$

Explanation:

The potential energy associated with a body (m) located at a given height (h) above a reference point is defined as:

$U=mgh$

At the reference point the potential energy is zero. In this case the body is below the reference point (the ceiling), therefore, the value of h is negative:

$U=2.2kg*9.8\frac{m}{s^2}*(-1.06m)\\U=-22.85J$

3 0

3 years ago