Using F=Gmm/r²
the ratio of their forces remains constant
Answer:
If the kinetic energy increases, the potential energy decreases, and vice-versa.
Explanation:
The amount of change in kinetic energy is equal to the amount of change in potential energy.
Answer:
a) a = 91.4 m / s², b) t = 0.175 s, c)
Explanation:
a) This is a kinematics exercise
v² = vox ² + 2a (x-xo)
a = v² - 0/2 (x-0)
let's calculate
a = 16² / 2 1.4
a = 91.4 m / s²
b) the shooting time
v = vox + a t
t = v-vox / a
t = 16 / 91.4
t = 0.175 s
c) let's use Newton's second law
F = ma
F = 7.9 91.4
F = 733 N
7.11x 10⁶J
Explanation:
Given parameters:
Speed of light = 3 x 10⁸m/s
Mass of object = 23.7g = 0.0237kg
Unknown:
Energy = ?
Solution:
From Einstein's equation, we see that mass and energy are equivalent using the expression below:
E = mc²
Substituting the parameters:
E = 3 x 10⁸ x 0.0237 = 7.11x 10⁶J
Learn more:
Energy brainly.com/question/5381158
#learnwithBrainly
Work is equal to a force over a distance and is equal to the change in kinetic energy, so
<span>
- Fd=ΔKE
</span>
<span>−Fd=1/2m<span>v22</span>−1/2m<span>v21</span></span>
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−F
</span>
We know that Ffric=kFnatural and Fnatural=mg so:
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−(k∗mg)</span><span>d=(−1/2<span>v21</span>)/−(k∗g)
</span><span>d=(−1/2×(14.6m/s<span>)2</span>)/−(0.137×9.8m/s)
</span><span>
d = 78.9m</span>
