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Virty [35]
3 years ago
6

Whats 3+3 for a prize~!u>

Mathematics
2 answers:
IgorC [24]3 years ago
7 0
3 + 3 = 6

If you want to add them up just get three candy bars and add another three, and you will get 6!
Vladimir [108]3 years ago
4 0
3+3=6 hope this helps!
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Factor 72x^2 + 72x^2+ 18x
malfutka [58]

Answer:

Use the app photomath

Step-by-step explanation:

7 0
3 years ago
Night Owl Motel rents rooms with 2 beds for $68 per night and rooms with 1 bed for $57 per night. One evening Night Owl Motel re
mixer [17]
1 bed room = 12
2 bed room = 15


68 x 15 = 1020
57 x 12 =   684
            -----------
1020 + 684 = $1704 (total made)

15 two-bed room + 12 one-bed room = 27 rooms in all
5 0
3 years ago
30 men repair a road in 56 days by working 6 hours daily. in how many days 45 men will repair same road by working 7 hours daily
zepelin [54]

Answer:

Case1:

Men : 30

Work : 1

Time (day×hr): 56×6 = 336 hr.

Case2:

Men : let it be m men.

Work: 1

Time: 45×7 = 315 hr.

Work being constant in both cases, men and time are in inverse proportion i.e, more men take less time.

Product of men and time is constant in both cases.

Therefore, 30×336=m×315

Or, 30×336/315 = m

Or, m = 32.

Hence, required number of men is 32.

Step-by-step explanation:

8 0
3 years ago
Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=​
Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0
3 years ago
3x-y=7<br> 2x+3y=12<br><br> how do you solve?
Dvinal [7]

Step-by-step explanation:

2x+3(-7+3x)=12

x=3

y=-7+3x3

y=2

(x,y)=(3,2)

6 0
3 years ago
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