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Virty [35]
4 years ago
6

Whats 3+3 for a prize~!u>

Mathematics
2 answers:
IgorC [24]4 years ago
7 0
3 + 3 = 6

If you want to add them up just get three candy bars and add another three, and you will get 6!
Vladimir [108]4 years ago
4 0
3+3=6 hope this helps!
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Maria plans to use fencing to build an enclosure or enclosures for her two horses. A single enclosure would be square shaped and
Gala2k [10]
Step 1
find the perimeter of a <span>single enclosure
perimeter of a square=4*b
where b is the long side of a square
area square=b</span>²
area square=2025 ft²
b²=2025-------> b=√2025-----> b=45 ft
<span>so
perimeter=4*45-------> 180 ft

step 2
</span>find the perimeter of a two individual enclosure
<span>perimeter=4*20+3*40------> 200 ft
area=20*40*2------> 1600 ft</span>²
<span>
therefore
fencing singular enclosure < fencing two individual enclosure
180 ft < 200 ft

</span>area singular enclosure > area two individual enclosure
2025 ft² > 1600 ft²<span>

the answer is the option
</span><span>a The singular enclosure would minimize cost because it requires 180 feet of fencing.</span><span>

</span>
5 0
3 years ago
Read 2 more answers
What is the sum of 1/6 and 5/12​
torisob [31]

Answer:

7/12

1/6 to 2/12 add 5/12 to get 7/12

3 0
3 years ago
9. shyam travelled 8 km 52 m by bus, 2 km 265 m by car. how much distance did he travel in all
Eduardwww [97]

Shyam travel total  10km 317m  distance ,when he travelled  8 km 52 m  by bus and 2 km 265 m  by car .

How to find the total distance travel by Shyam ?

Shyam travelled distance by bus =8 km 52 m

Shyam travelled distance by car =2 km 265 m

Total distance travelled by shyam is

Total distance= distance travelled by car + distance travelled by bus

Total distance

=2 km 265 m+8 km 52 m\\=(2+8)km(265+52)m\\=10km317m

Learn more about the distance travel is here :

brainly.com/question/28048546

#SPJ4

7 0
2 years ago
*5) x—&gt; 1 — x<br><br> Help please will really appreciate it
Paha777 [63]
Hey I’m sorry but I do not know the answer.
3 0
3 years ago
Permutations of the word "Congratulations"​
Mice21 [21]

Answer:

There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is  14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is  14!/(23)=10,897,286,400

5 0
3 years ago
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