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jeka94
3 years ago
10

A sample of tendon 3.00 cm long and 4.00 mm in diameter is found to break under a minimum force of 128 N. If instead the sample

had been 1.50 cm long and of uniform composition and cross-sectional area, what minimum force would have been required to break it
Physics
1 answer:
Hatshy [7]3 years ago
3 0

Answer:128 N

Explanation:

Sample of 3 cm and 4 mm diameter found to break under a minimum force of 128 N .

If sample is 1.5 cm long with same cross-sectional area then minimum force required to break is also 128 N because the applied force is same for any length and diameter of tendon.        

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What are the 2 main categories of boat hull designs and how does each one function? What are the positives and negatives of each
defon

Answer:

The two main categories of boat hull designs are;

  • Displacement Hull
  • Planning Hull

Explanation:

<u>Displacement Hull</u>

This type of boat hull is designed to displace certain amount of water as it moves. This displacement enable it to insert its body into the water and continue to displace water from its was as it moves. The weight of water displaced is usually equal to the weight of the boat.

Displacement Hull and Speed

Because of the need to displace water from its path to enable it insert itself into the water body for movement, the speed is usually slow compared to planning hull boats.

Displacement Hull Types:

  • Round bottomed hull boat: Their hulls are made to have a round bottom in order to displace water and move smoothly through it. It can move quietly at low speed. How ever, they require complex stabilizer to control them from banking.
  • Multi hull boat: This type of hull design has a large and long beam that make it to be very stable on the water body. They usually have ends pointed downwards for proper insertion and displacement. However, they don't turn easily on small space due to their large beam requirement.

<u>Planning Hull</u>

Planning hull boats are designed to slide very fasly on the water surface with very little or no insertion. They require boat engines that operates at a very high revolution per minute(rpm).

When at rest, that is at zero speed, they behave like displacement hull boats but only a small amount of water is displaced a they are usually lighter.

Planning hull boats can operate in three modes:

  • Displacement mode: This mode is used when planning hull boats move at extremely slow speed. At this mode, they push water side ways as they move.
  • Planning mode: This mode is activated as the speed of the boat increases to enable it glide on the surface of the water.
  • Plowing mode: This mode is reach when the bow of the boat is trusted up and suspended as it slides through the surface of the water at a very high speed

Planning Hull and Speed

The speed of planning hull boats is very high when compared to displacement hull boats. This high speed of operation is powered by high rpm engines to enable it slide on the surface of the water.

Planning Hull Types/Merit and Demerit

  • Flat Bottom Hull: Their hull is flat bottom shaped and has a draft that supports its suspension on water on a stable manner. Suitable for stable water. However, it moves haphazardly on shaky water.
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6 0
4 years ago
The initial speed of a body is 3.28 m/s. What is its speed after 2.32 s if it accelerates
Helga [31]
Final velocity = initial velocity + acceleration * time

v = u + at

v = 3.28 + 2.32 * 2.08

v = 3.28 + 4.83

<u>v = 8.11 m/s</u>
6 0
3 years ago
What characteristics of EM waves did you discover?
jarptica [38.1K]

The characteristics of electromagnetic waves typically represent as follows:

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  • The direction of the electric field and the magnetic field are perpendicular to each other. The direction of both is perpendicular to the direction of the wave propagation.
  • The shape of electromagnetic waves is transverse waves.
  • It has general wave characteristics like polarization, reflection, refraction, interference, and diffraction.
  • The amount of the electric field (E) is directly proportional to the magnitude of the magnetic field, with the relationship E = cB.
  • The universal constant of the velocity of electromagnetic waves in a vacuum is \boxed{ \ c = 3 \times 10^8 \ m/s. \ }
  • The speed at which electromagnetic waves propagate depends merely on the electrical and magnetic properties of the medium that it travels on.
  • Because electromagnetic waves do not contain an electric charge, they do not experience any possible deviation in the electric or magnetic fields.
<h3>Further explanation</h3>
  • Two physicists who contributed significantly to developing the concept of electromagnetic waves are Faraday and Maxwell around 1831-1864.
  • From the observations, Faraday suggested that changes in the magnetic field cause an electric charge to flow in the loop of wire, contributing in the emergence of an electric field.
  • Maxwell proposed a reverse process, which is a change in the electric field will generate a magnetic field.
  • As follows, according to Faraday's Law, changes in sinusoidal magnetic fields generate electric fields which also change sinusoidally.
  • Meantime, according to Maxwell's Hypothesis, changes in sinusoidal electric fields generate magnetic fields which also change sinusoidally.
  • Furthermore, there is a process of combining electric and magnetic fields that propagate in all directions called electromagnetic waves.
<h3>Learn more </h3>
  1. About vector components brainly.com/question/1600633
  2. Determine the shortest wavelength in electron transition brainly.com/question/4986277
  3. Particle's speed and direction of motion brainly.com/question/2814900

Keywords: the characteristics, electromagnetic waves, transverse, vacuum, electric fields, magnetic, perpendicular, propagation, Maxwell, Faraday, the speed, polarization, reflection, refraction, interference, and diffraction

4 0
4 years ago
Read 2 more answers
Which of the following expressions will have units of kg⋅m/s2? Select all that apply, where x is position, v is velocity, m is m
netineya [11]

Answer: m \frac{d}{dt}v_{(t)}

Explanation:

In the image  attached with this answer are shown the given options from which only one is correct.

The correct expression is:

m \frac{d}{dt}v_{(t)}

Because, if we derive velocity v_{t} with respect to time t we will have acceleration a, hence:

m \frac{d}{dt}v_{(t)}=m.a

Where m is the mass with units of kilograms (kg) and a with units of meter per square seconds \frac{m}{s}^{2}, having as a result kg\frac{m}{s}^{2}

The other expressions are incorrect, let’s prove it:

\frac{m}{2} \frac{d}{dx}{(v_{(x)})}^{2}=\frac{m}{2} 2v_{(x)}^{2-1}=mv_{(x)} This result has units of kg\frac{m}{s}

m\frac{d}{dt}a_{(t)}=ma_{(t)}^{1-1}=m This result has units of kg

m\int x_{(t)} dt= m \frac{{(x_{(t)})}^{1+1}}{1+1}+C=m\frac{{(x_{(t)})}^{2}}{2}+C This result has units of kgm^{2} and C is a constant

m\frac{d}{dt}x_{(t)}=mx_{(t)}^{1-1}=m This result has units of kg

m\frac{d}{dt}v_{(t)}=mv_{(t)}^{1-1}=m This result has units of kg

\frac{m}{2}\int {(v_{(t)})}^{2} dt= \frac{m}{2} \frac{{(v_{(t)})}^{2+1}}{2+1}+C=\frac{m}{6} {(v_{(t)})}^{3}+C This result has units of kg \frac{m^{3}}{s^{3}} and C is a constant

m\int a_{(t)} dt= \frac{m {a_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{4}} and C is a constant

\frac{m}{2} \frac{d}{dt}{(v_{(x)})}^{2}=0 because v_{(x)} is a constant in this derivation respect to t

m\int v_{(t)} dt= \frac{m {v_{(t)}}^{2}}{2}+C This result has units of kg \frac{m^{2}}{s^{2}} and C is a constant

6 0
3 years ago
As compared to the asthenosphere, the lithosphere is ____________. a. hotter and more able to flow b. hotter and less able to fl
Mnenie [13.5K]

Answer:

its a solid but can flow

Explanation:

those answers to choose from are wrong

8 0
2 years ago
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