A 9,100-microfarad [muF] capacitor is charged to 22 volts [V]. If the capacitor is completely discharged through an iron rod
0.2 meters [m] long and one-quarter centimeter [cm] in diameter, resulting in 80% of the stored energy being transferred to the rod as heat, how much does the temperature of the rod increase? Give your answer in kelvin [K].
Data you may need:
Specific Gravity of iron: SG = 7.874
Specific heat of iron: CP = 0.450 J/(g K)
Data you may need:
Specific Gravity of iron: SG = 7.874
Specific heat of iron: CP = 0.450 J/(g K)
1 answer:
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Since initial velocity is zero hence , u = 0
=> d = 1/2 * a * t2
on solving we get
d = 86.436 metres
Note ; Here Gravitational Acceleration is take as , g = 9.8 m/s2