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Yakvenalex [24]
3 years ago
14

A 9,100​-microfarad ​[mu​F] capacitor is charged to 22 volts​ [V]. If the capacitor is completely discharged through an iron rod

0.2 meters​ [m] long and​ one-quarter centimeter​ [cm] in​ diameter, resulting in 80​% of the stored energy being transferred to the rod as​ heat, how much does the temperature of the rod​ increase? Give your answer in kelvin​ [K].  
Data you may​ need:
Specific Gravity of​ iron: SG = 7.874
Specific heat of​ iron: CP = 0.450 ​J/(g K)

Physics
1 answer:
MakcuM [25]3 years ago
5 0

Answer:

The temperature rises by 0.52K

Explanation:

Detailed explanation and calculation is shown in the image below

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Answer:

(i) It will take longer (75/22 times) the time to boil a given quantity of water compared to when the current is working at its rated capacity

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Explanation:

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t₂/t₁ =3000/880 = 75/22

Hence the kettle will take 75/22 multiplied by the time it takes when working at rating capacity to boil a given quantity of water

(ii) This is so because the power consumption already factored in the electrical installation as well as the type of appliances utilized in the home allow for several low power rating consumption and few high power rating consumption

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