A 9,100-microfarad [muF] capacitor is charged to 22 volts [V]. If the capacitor is completely discharged through an iron rod
0.2 meters [m] long and one-quarter centimeter [cm] in diameter, resulting in 80% of the stored energy being transferred to the rod as heat, how much does the temperature of the rod increase? Give your answer in kelvin [K].
Data you may need:
Specific Gravity of iron: SG = 7.874
Specific heat of iron: CP = 0.450 J/(g K)
Data you may need:
Specific Gravity of iron: SG = 7.874
Specific heat of iron: CP = 0.450 J/(g K)
1 answer:
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Answer:
740 N
Explanation:
We are given that
Radius,r=0.3 m
Torque,
We have to find the magnitude of the static frictional force.
According to question
Torque by engine=Torque by static friction
Hence, the magnitude of static frictional force=740 N
Answer:
F = 5.256 x
Explanation:
From the work energy theorem we know that:
The net work done on a particle equals the change in the particles kinetic energy:
W = F.d, ΔK =
where:
W = work done by the force
F = Force
d = Distance travelled
m = Mass of the car
vf, vi = final and initial velocity of the car
kf, ki = final and initial kinetic energy of the car
Given the parameters;
m = 830kg
vi = 1.9 m/s
vf = 0 km/h
d = 0.285 m
Inserting the information we have:
F.d =
F =
F =
F = 5.256 x