Question

A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to which the submarine can go without damaging the window is closest to?a. 680mb. 750mc. 1200md. 1327m

Answer 1

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = $5.20 \times 10^{5}$ N

         g = 9.8 m/s

         radius = $\frac{diameter}{2}$

                    = $\frac{30 cm}{2}$ = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = $\rho \times g \times h \times A$

or,      h = $\frac{F}{\rho \times g \times A}$        

       h = $\frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}$

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.