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aivan3 [116]
3 years ago
13

Nuclear fission can be described as a chain reaction. a. True b. False

Physics
2 answers:
Semenov [28]3 years ago
8 0

Answer : The given statement is, True.

Explanation :

Nuclear fission : It is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

In fission process, protons and neutrons are produced and larger amount of energy is released.

Nuclear fission can be described as a chain reaction.

In nuclear reactor, neutron hits the uranium nucleus and the uranium nucleus splits into two nuclei and three neutrons. These three neutrons further hit the uranium nucleus and the uranium nucleus split into two nuclei and these 3 neutrons produces 9 neutrons.

So, yes the nuclear fission can be described as a chain reaction.

monitta3 years ago
6 0

Answer: The correct answer is True.

Explanation:

Nuclear fission reactions is a type of nuclear reactions. In these nuclear reactions, one heavier nuclei splits into two or more lighter nuclie's. This process produces a series of  neutrons and protons and release a large amount of energy.

Nuclear chain reactions are a series of fission reactions which is initiated by the neutron that is produces in the previous fission reaction. The neutrons in turn produces neutrons and the process further continues.

So Yes, nuclear fission can be described as a chain reaction.

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Answer:

A and B are correct both are correct

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A 0.18-kg turntable of radius 0.32 m spins about a vertical axis through its center. A constant rotational acceleration causes t
borishaifa [10]

Answer:

Angular acceleration will be 18.84rad/sec^2

Explanation:

We have given that mass m = 0.18 kg

Radius r = 0.32 m

Initial angular velocity \omega _i=0rev/sec

And final angular velocity \omega _f=24rev/sec

Time is given as t = 8 sec

From equation of motion

We know that \omega _f=\omega _i+\alpha t

24=0+\alpha \times 8

\alpha =3rev/sec^2=3\times 2\times \pi rad/sec^2=18.84rad/sec^2

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4 0
3 years ago
A force of 55N accelerates a 7.5kg wagon at 5.3 m/s^2 along a road. How large is the frictional force?
Varvara68 [4.7K]

Answer:

<h2>15.25 N</h2>

Explanation:

       A force of 55\text{ }N is acting on a wagon along the road. The wagon weights 7.5\text{ }kg. Acceleration of the wagon is given as 5.3\text{ }\frac{m}{s^{2}}.

       Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.

       Gravitational Force and Normal Reaction cancel out each other.

       Net External Force = Mass of system/wagon \times Acceleration of wagon

       F_{ext}-F_{friction}=(7.5\text{ }kg)\times(5.3\text{ }\frac{m}{s^{2}})=39.75\text{ }N\\55\text{ }N-F_{friction}=39.75\text{ }N\\F_{friction}=15.25\text{ }N

F_{friction} has a negative sign because it opposes the motion of the wagon.

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3 years ago
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3 0
2 years ago
A. A PH202 student lives next to a construction site and sees a crane with a wrecking ball demolish the building next door. The
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Answer:

The length of cable is 12.5 m

Explanation:

Since, the wrecking ball completes 1 oscillation, in the same time, as it takes for the rock to complete 5 oscillations.

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Since,

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Squaring on both sides:

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Therefore,

L₁ = 25 (0.5 m)

<u>L₁ = 12.5 m</u>

8 0
3 years ago
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