I think it is D a light bulb
Answer:
(a) The equivalent spring constant is 598.485 N/m
(b) The work done is 46.926 J
Explanation:
From Hooke's law of elasticity
K (spring constant) = F/e
F is the range of force exerted = 237 - 0 = 237 N
e is the extension of bowstring = 0.396 m
K = F/e = 237/0.396 = 598.485 N/m
Work done = 1/2 Fe = 1/2 × 237 × 0.396 = 46.926 J
Answer:
A. potassium
Explanation:
Potassium is expected to have the greater atomic radius from the given choices of element.
Atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid states of metals.
- Across a period, the atomic radii decreases progressively from left to right.
- This is due to the progressive increase in the nuclear charge without increase in the number of electronic shells.