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4 years ago

15

It takes you 7.7 min to walk with an average velocity of 1.7 m/s to the north from the bus stop to the museum entrance. How far

did you walk? Answer in units of m.

1 answer:

Juli2301 [7.4K]4 years ago

6 0

Distance equals velocity times time:
x = v*t = 1.7 m/s * 7.7min * 60 s/min = 785.4 m

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An oscillator creates periodic waves on two strings made ofthe same material. The tension is the same in both strings.If the str

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Answer:

c. wavelength

Explanation:

The speed of the wave on the string is given by

$v= \sqrt{\frac{T}{\mu} }$

Here, \mu is the mass per unit length and T is the tension in the string.

For the different thickness, the mass per unit length is different. Therefore, the wave speed is different in the two strings.

The frequency of the oscillations depends upon the oscillator. So, the frequency is same for the two strings by using same oscillator.

The frequency and speed relation is,

f= γλ

λ= f/γ

Since frequency is constant, the wavelength of the waves different as the speeds are different.

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3 years ago

. An object has a position given by ~r(t) = [3.0 m − (4.00 m/s)t]ˆı + [6.0 m − (8.00 m/s2 )t 2 ]ˆ , where all quantities are in

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Answer:

(c) 16 m/s²

Explanation:

The position is $r(t) = [3.0 \text{ m} - (4.00 \text{ m/s})t]\hat{i} + [6.0 \text{m} - (8.00 \text{ m/s}^2 )t^2 ]\hat{j}$ .

The velocity is the first time-derivative of <em>r(t).</em>

<em /> $v(t) = \dfrac{d}{dt}r(t) = -4.00\,\hat{i} -16t\,\hat{j}$ <em />

The acceleration is the first time-derivative of the velocity.

$a(t) = \dfrac{d}{dt} v(t) = -16\hat{j}$

Since <em>a(t)</em> does not have the variable <em>t</em>, it is constant. Hence, at any time,

$a = -16\hat{j}$

Its magnitude is 16 m/s².

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3 years ago

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In collision type of problems since momentum is always conserved

we can say

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$v_{2f} - v_{1f} = e(v_{1i} - v_{2i})$

so above two equations are required to find the velocity after collision

here the change in velocity occurs due to the contact force while they contact in each other

so this is the impulse of collision while they are in contact with each other while in collision which changes the velocity of two colliding objects

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3 years ago

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If you are holding a book and you let go of it, why does it fall? Explain in terms of forces, potential energy, and kinetic ener

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Answer:

Let the mass of the book be "m", acceleration due to gravity be "g", velocity be "v" and height be "h".

Now if we are holding a book at a certain height (h), <em><u>the potential energy will be maximum which is equal to mass× acceleration due to gravity× height (= mgh)</u>.</em>

(Remember: kinetic energy =0)

Now we consider that the book is dropped, in this case a force will act downward towards the centre of the earth, <em><u>Force= mass× acceleration due to gravity (F=mg)</u></em>. It is equal to the weight of the book.

While the book is falling, the potential energy stored in the book converts into kinetic energy and strikes the floor with <em><u>the maximum kinetic energy= (1/2)×mass×velocity² (=1/2mv²)</u>.</em>

(Remember: kinetic energy=0)

Due to this process the whole energy is conserved.

As the potential energy decreases kinetic energy increases.

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3 years ago

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hichkok12 [17]

<span>The part of the atom that accounts for electricity is the "Electron"

In short, Your Answer would be Option A

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3 years ago

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