Answer:
Step-by-step explanation:
This problem is similar to many others in which the sum of two quantities and their difference are given. The solution can be found easily when the equations for the relations are written in standard form.
<h3>Setup</h3>
Let s and h represent numbers of sodas and hot dogs sold, respectively. The given relations are ...
- s +h = 235 . . . . . combined total
- s -h = 59 . . . . . . difference in the quantities
<h3>Solution</h3>
Adding the two equations eliminates one variable.
(s +h) +(s -h) = (235) +(59)
2s = 294 . . . . simplify
s = 147 . . . . . .divide by 2
h = 147 -59 = 88 . . . . h is 59 less
147 sodas and 88 hot dogs were sold.
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<em>Additional comment</em>
The solution to a "sum and difference" problem is always the same. One of the numbers is half the sum of those given, and the other is half their difference. ((235-59)/2 = 88)
Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

Answer:
She increased 80% the practise time
Step-by-step explanation:
The question is incomplete, the following is missing:
<em>by how much did she increase the time she practised each day?
</em>
From Monday to Wednesday she increased 90 - 50 = 40 minutes the practise time.
To compute the increment as a percentage use: increment/reference *100
In this case, that is: 40/50*100 = 80%, where 50 minutes is taken as a reference.
Answer:
Here, b represents one loaf of bread and m represents the one gallon of milk.
As per the statement:
Arah went to the grocery store and bought 4 loaves of bread and 1 gallon of milk for $12.
⇒
It is also given that the next week, Sarah bought 2 loaves of bread and 3 gallons of milk for $13.50.
⇒
Then; system of equation :
.....[1]
.....[2]
Solve for b and m using above system of equations.
Multiply equation [2] by 2 we get;
.....[3]
Subtract equation [1] from [3] we get;
Combine like terms;
Divide both sides by 5 we get;
m = $3
Substitute the value of m in equation [1] we get;

Subtract 3 from both sides we get;
Divide both sides by 4 we get;
b = $2.25
Therefore, cost of one loaf of bread (b) and one gallon of milk (m) are:
$2.25 ad $3
Diameter of the circle is BD as shown, as indicated and passed through center where BD passes, triangle ABD is a right triangle with angle ABD as the right angle. It means ADB and ABD are complementary which means
AB = 140 degree
AD=40 degree