Question

These two beakers represent solutions of HCl and NaOH. Describe a third beaker showing the ions that remain after the reaction has gone to completion.
The third beaker contains __ OH- ion(s), __ Cl- ion(s), __ Na+ ion(s), and __ H+ ion(s)

Answer 1

Number of ions in the third beaker:

4 Cl⁻ ions

5 Na⁺ ions

1 OH⁻ ion

Explanation:

If you mix the backers the following chemical reaction will occur:

HCl + NaOH → NaCl + H₂O

In the ionic form you write the equation:

H⁺ (aq) + Cl⁻ (aq) + Na⁺ (aq) + OH⁻ (aq) → Cl⁻ (aq) + Na⁺ (aq) + H₂O (l)

where:

(aq) - aqueous (dissolved in water)

(l) - liquid

Number of ions in the first beaker:

4 Cl⁻ ions

4 H⁺ ions

Number of ions in the second beaker:

5 Na⁺ ions

5 OH⁻ ions

Number of ions in the third beaker:

4 Cl⁻ ions

5 Na⁺ ions

1 OH⁻ ion

The rest of H⁺ and OH⁻ ion reacted to form water.

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