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zheka24 [161]
3 years ago
8

There are 7 named classes of hazardous materials. O True O False

Chemistry
1 answer:
Anika [276]3 years ago
7 0
False

there is actually 9
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If we read the reaction as X + Y → Z + Q it is<br> A. endothermic<br> B. exothermic
Korvikt [17]
As you can see in the picture we have +ΔH so that means for this reaction we need to GET heat. so the answer is A. endothermic :))
i hope this is helpful
have a nice day 
4 0
3 years ago
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What is the electron configuration of an element with atomic number 15? A. 1s2 2s2 2p6 B. 1s2 2s2 2p6 3s2 3p5 C. 1s2 2s2 2p6 3s2
kipiarov [429]
B 
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4 0
3 years ago
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What is the difference between an enzyme and a catalyst?
stealth61 [152]
Catalyst- chemical that increases the rate of a chemical reaction without itself being changed from the reaction. Enzyme- substance produced by a living organism that acts as a catalyst to bring about a particular biochemical reaction. Hope it helps.
6 0
3 years ago
Which property can be used to tell gold and pyrite apart?
zubka84 [21]

Answer:

D. Malleability

Explanation:

Gold is made up of the element Au and it is a metal.

Pyrite is iron sulfide and it is a non-metal.

  • They have very similar appearance to such an extent that pyrite is widely called the fool's gold.
  • To distinguish between the two, we simply explore their metallic properties.
  • Gold is malleable. Pyrite is not. It will crumble under pressure.
6 0
3 years ago
The ka of hypochlorous acid (hclo) is 3.0 ⋅ 10−8 at 25.0 °c. calculate the ph of a 0.0375m hypochlorous acid solution.
Scrat [10]
We can set up an ICE table for the reaction:                      
                      HClO          H+     ClO-
Initial              0.0375       0        0
Change         -x               +x      +x
Equilibrium    0.0375-x     x        x

We calculate [H+] from Ka:     
     Ka = 3.0x10^-8 = [H+][ClO-]/[HClO] = (x)(x)/(0.0375-x)

Approximating that x is negligible compared to 0.0375 simplifies the equation to         
     3.0x10^-8 = (x)(x)/0.0375     
     3.0x10^-8 = x2/0.0375     
     x2 = (3.0x10^-8)(0.0375) = 1.125x10^-9     
     x = sqrt(1.125x10^-9) = 0.0000335 = 3.35x10^-5 = [H+]
in which 0.0000335 is indeed negligible compared to 0.0375.

We can now calculate pH:     
     pH = -log [H+] = - log (3.35 x 10^-5) = 4.47
6 0
4 years ago
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