There are 7 named classes of hazardous materials. O True O False

HSiCl3+H2O=H10Si10O15+HCl

tiny-mole [99]

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Explanation:

Step 1: To make Si equal on both sides. put 10 in front of HSiCl3

10 HSiCl3+ H2O →H10Si10O15+ HCl

Step 2: By putting 30 in front of HCl, Cl can be balanced

10 HSiCl3+ H2O →H10Si10O15+ 30 HCl

Step 3: Now, balance O by putting 15 in front of H2O

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Hence the balanced equation is:

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

5 0

4 years ago

The valence electrons largely determine the

ss7ja [257]

Valence electrons largely determine the chemical properties of an element.

8 0

3 years ago

In a voltaic cell, the salt bridge acts to:

AleksAgata [21]

Provide a direct contact between the oxidation and reduction electrodes - A

6 0

4 years ago

Read 2 more answers

How much heat is required to warm 50.0 g of ice from -10.0oC to 0.00oC, melt the ice, warm the water from 0.00oC to 100.0oC, boi

ludmilkaskok [199]

The total heat required to convert the ice to steam is 155,000 J.

The given parameters:

Mass of the ice, m = 50 g
Initial temperature of the ice, t = -10 ⁰C
Final temperature of the ice, T = 0⁰C, 100⁰C and 120⁰C
Specific heat capacity of water = 4.184 J/g⁰C
Heat of fusion of ice, = 333.55 J/g
Heat of vaporization, = 2,230 J/g

The heat required to raise the temperature to 0⁰C is calculated as;

$Q = mc\Delta t\\\\Q_1 = 50 \times 4.184 \times (0 - (-10))\\\\Q_1 = 2092 \ J$

The heat required to melt the ice is calculated as follows;

$Q_2 = mL_f\\\\Q_2 = 50 \times 333.55 \\\\Q_2 = 16,677.5 \ J$

The heat raise the temperature to 100⁰C is calculated as;

$Q_3 = 50 \times 4.184 \times (100 - 0)\\\\Q_3 = 20,920 \ J$

The heat required to boil the water is calculated as follows;

$Q_4 = mL_v\\\\Q_4 = 50 \times 2230\\\\4_4 = 111,500 \ J$

The heat raise the temperature to 120⁰C is calculated as;

$Q_5 = 50 \times 4.184 \times (120 - 100)\\\\Q_5 = 4,184 \ J$

The total heat required is calculated as follows;

$Q_t = Q_1 + Q_2 + Q_3 + Q_4 + Q _5 \\\\Q_t = 2092 + 16,677.5 + 20,920 + 111,500 + 4,184\\\\Q_t = 155,373.5 \ J\\\\Q_t \approx 155,000 \ J$

Learn more about heat capacity here: brainly.com/question/16559442

4 0

3 years ago

The early periodic table grouped elements based on similar properties. Which element would be grouped with sodium using this pri

Reika [66]

Answer:

C.Potassium

Explanation:

As we know that Potassium is a mineral also at the same time it is an electrolyte. It helps for muscles work involves the muscles so that the heartbeat and breathing could be controlled.

Now as per the periodic table on an early basis that depends upon the similar properties so the element that should be grouped with the sodium is Potassium

hence, the option c is correct

8 0

4 years ago