Answer:
temperature at 326.44 K system achieve equilibrium
Explanation:
given data
mass of block of ice = 4.6 kg
temperature = 263 K
thermal contact = 15.7-kg
specific heat of silver cAg = 233 J/kg-K
initially temperature = 1052 K
to find out
what temperature will the system achieve equilibrium
solution
first we consider final temperature of the system is T
we know that specific heat of water (C w) = 4186 J(kg K)
and
specific heat of ice ( C i ) = 2030 J/(kg K)
and
latent heat of fusion of ice ( Lf ) = 3.33 × J/kg
and we know that system is insulated
so heat lost by silver = heat generated by ice .................1
so we can say
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
put here value we get
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × + 4.6 × 4286 × ( T - 273 )
solve we get
T = 326.44 K
so temperature at 326.44 K system achieve equilibrium