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Lapatulllka [165]
3 years ago
12

If astronauts could travel at v disagree. 0.945c, we on Earth would say it takes 4.200 945 4 44 years to reach pha centaur 42Ф

Çgint ears away. The astronauts (a) How much time passes on the astronauts' clocks? Your response is within 10% of the correct value. This may be due to roundoff error or you could have a mistake in your calculation. results to at least four-digit accuracy to minimize roundoff error. years arn out all men mediate (b) What is the distance to Alpha Centauri as measured by the astronauts?
Physics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

1.3734 years pass on the astronauts' clock.

The distance measured by astronauts is 1.22*10^{16} \ m

Explanation:

The fomula for time dilation is:

t'=t\sqrt{1-\frac{v^2}{c^2} }

where t' is the time observed by the astronauts, t is the time observed form Earth, v is the velocity of the astronaut and c is the velocity of light in a vacuum.

Replacing our values: t=4.2 year, v=0.945c

t'=4.2\sqrt{1-\frac{{(0.945c)}^2}{c^2} } =\\\\=4.2\sqrt{1-0.8930 }=4.2*0.3270=1.3734\ years

The distance measured by astronauts will be their speed multolied by the time is takes them to get to alpha centauri:

D=v*t'=0.945*c*1.3734=0.945*3.00*10^8 m/s*1.3734*3.154*10^7

To acomodate fot units we write the speed of light in m/s and the amount of seconds in a year, so the resulting distance will be in meters.D=1.22*10^{16} \ m

We should compare this to the distance measured from Earth which is D=c*t=3.00*10^8 m/s*4.2*3.154*10^7=3.974*10^{16}\ m

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Katena32 [7]

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The hydrogen molecule is a form that two hydrogen atoms share their electrons decreasing the total energy of the molecule, this bond has a covalent and hydrogen bonding characteristic.

In a stellar explosion, the energy released increases the energy of the hydrogen atom, for which we have two possibilities:

  • Its electron is lost, so we are in a single proton, in the case of structures where the proton and the elector are
  • The hydrogen atom remains but the energy of the atom is very high so the kinetic energy of the electron prevents the electron from being shared by the other atom and the molecule cannot be formed.

When the atoms are thrown into space, the separation between them is so high that it does not allow electrons to be shared and molecules cannot be formed either.

In conclusion, the decrease in energy in the hydrogen molecule is what allows its formation on Earth, but in stars the great energy of the explosion has a kinetic energy so great that electrons cannot join another atom, which is why the hydrogen has only one atom.

Learn more about the Hydrogen atom here:

brainly.com/question/22464200

6 0
2 years ago
How fast does light year travel
KIM [24]
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5 0
3 years ago
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You ran a power plant what could you do to make this generator produce electricity
DIA [1.3K]
You could use a magnetic generator or you could use hydraulic power
8 0
3 years ago
A man starts walking north at 3 ft/s from a point P. Five minutes later a woman starts walking south at 4 ft/s from a point 500
mrs_skeptik [129]

Answer:

ds/dt = 6.98 ft/s

Explanation:

Given:

- The speed of man due north Vm = 3 ft/s

- The speed of woman due south Vw = 4 ft/s

- Woman starts walking 5 mins later than man

Find:

At what rate are the people moving apart 15 min after the woman starts walking?

Solution:

- The total time for which the man is walking due north from P, is Tm:

                                   Tm = 5 + 15 = 20 mins

- The total distance traveled by man in Tm mins is:

                                   Dm = Tm*Vm

                                   Dm = 20*60*3

                                   Dm = 3,600 ft

- The total time for which the woman is walking due south from 500 ft due east from P, is Tw:

                                   Tw = 15 = 15 mins

- The total distance traveled by man in Tw mins is:

                                   Dw = Tw*Vw

                                   Dw = 15*60*4

                                   Dw = 3,600 ft

- The displacement between man and woman at any instance is (s) which can be related by pythagoras theorem as follows:

                                   s^2 = (dm + dw)^2 + 500^2

Where, dm : Distance travelled by man at any time Tm

            dw : Distance travelled by woman at any time Tw

- Differentiate s with respect to t:

                                   2s*ds/dt = 2*(dm + dw)*(Vm + Vw)

                                   s*ds/dt = (dm + dw)*(Vm + Vw)

                                   ds/dt = [ (dm + dw)*(Vm + Vw) ] / s

- Evaluate the rate of separation of man and woman ds/dt by evaluating at instance Tm = 20 mins and Tw = 15 mins. We have:

                 ds/dt = [ (Dm + Dw)*(Vm + Vw) ] / sqrt ( (Dm + Dw)^2 + 500^2 )

- Plug in the values:

                 ds/dt = [ (3600 + 3600)*(3 + 4) ] / [sqrt ( (3600 + 3600)^2 + 500^2 )]  

                ds/dt = 6.98 ft/s

                 

           

7 0
3 years ago
A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0
3 years ago
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