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Lapatulllka [165]
3 years ago
12

If astronauts could travel at v disagree. 0.945c, we on Earth would say it takes 4.200 945 4 44 years to reach pha centaur 42Ф

Çgint ears away. The astronauts (a) How much time passes on the astronauts' clocks? Your response is within 10% of the correct value. This may be due to roundoff error or you could have a mistake in your calculation. results to at least four-digit accuracy to minimize roundoff error. years arn out all men mediate (b) What is the distance to Alpha Centauri as measured by the astronauts?
Physics
1 answer:
kolezko [41]3 years ago
6 0

Answer:

1.3734 years pass on the astronauts' clock.

The distance measured by astronauts is 1.22*10^{16} \ m

Explanation:

The fomula for time dilation is:

t'=t\sqrt{1-\frac{v^2}{c^2} }

where t' is the time observed by the astronauts, t is the time observed form Earth, v is the velocity of the astronaut and c is the velocity of light in a vacuum.

Replacing our values: t=4.2 year, v=0.945c

t'=4.2\sqrt{1-\frac{{(0.945c)}^2}{c^2} } =\\\\=4.2\sqrt{1-0.8930 }=4.2*0.3270=1.3734\ years

The distance measured by astronauts will be their speed multolied by the time is takes them to get to alpha centauri:

D=v*t'=0.945*c*1.3734=0.945*3.00*10^8 m/s*1.3734*3.154*10^7

To acomodate fot units we write the speed of light in m/s and the amount of seconds in a year, so the resulting distance will be in meters.D=1.22*10^{16} \ m

We should compare this to the distance measured from Earth which is D=c*t=3.00*10^8 m/s*4.2*3.154*10^7=3.974*10^{16}\ m

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Answer:

Explanation:

Given

Weight of person W=652\ N

At highest point Magnitude of the normal force F=585\ N

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F_{net}=W+F_c

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F_c=\dfrac{mv^2}{r}

F_{net}=F_{n}= Normal Force

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At bottom point centripetal force is towards the bottom

F_n=F_c+W

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Object 1 of mass m moves with speed v in the positive direction. Object 2 of mass 3 m moves with speed 4 v in the negative x-dir
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Answer:

This means that the kinetic energy of second object is 48times that of the first object

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion e.g motion of an accelerating car. Mathematically,

Kinetic energy = 1/2mv² where;

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If Object 1 of mass m moves with speed v in the positive direction, its kinetic energy will be expressed as;

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For Object 2 of mass 3m moving with speed 4v in the negative x-direction, its kinetic energy can be expressed as;

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