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Lesechka [4]
3 years ago
14

PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS

Mathematics
2 answers:
ladessa [460]3 years ago
6 0

Answer:

-8 vertical in negative one horizontal

Step-by-step explanation:

Mark me brainliest!!

lakkis [162]3 years ago
3 0

Answer:

\huge\boxed{\text{D) 1 vertical and 8 horizontal}}

Step-by-step explanation:

If you simply look at the point at the vertex of the right angle of both triangles, you can see that in figure 1 the point is at (-5, 1) and in figure 2 it is (3,2).  The shift between the x and y are 8 in the x and 1 in the y.

Hope it helps :)

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A blimp, suspended in the air at a height of 600 feet, lies directly over a line from a sports stadium to a planetarium. If an a
Molodets [167]

Step-by-step explanation:

so, this sounds like the blimp is located between the stadium and the planetarium.

we have a triangle :

the ground distance between the stadium and the planetarium is the baseline.

and the 2 lines of sight from the blimp on one side to the stadium and on the other side to the planetarium are the 2 legs.

we know the height of this triangle is 600 ft.

the angle of depression down to the stadium is 37°. which makes the inner triangle angle at the ground point at the stadium also 37°.

and the angle of depression down to the planetarium is 29°. which makes the inner triangle angle at the ground point at the planetarium also 29°.

and because the sum of all angles in a triangle is always 180°, we know the angle at the blimp is

180 - 37 - 29 = 114°

in order to solve this triangle, we need to split it into 2 right-angled triangles by using the height of the main triangle as delimiter.

we get a stadium side and a planetarium side triangle.

the baselines (Hypotenuses) of the 2 triangles are the corresponding lines of sight from the blimp.

the height of the large triangle is also a height and a leg in each small triangle.

and the stadium side part of the large baseline (between ground point and intersection with the height) is the second leg for the stadium side triangle.

and correspondingly, the planetarium side part of the large baseline (between ground point and intersection with the height) is the second leg for the planetarium side triangle.

the inner blimp angle of the stadium side triangle is

180 - 37 - 90 = 53°

and the inner blimp angle of the planetarium side triangle is

180 - 29 - 90 = 61°

now we can use the law of sine to get the lengths of the 2 parts of the baseline of the large triangle.

and when we add these 2 numbers we get the distance between stadium and planetarium.

law of sine is

a/sin(A) = b/sin(B) = c/sin(C)

with the sides being opposite of the associated angles.

for the stadium side triangle we get

part1/sin(53) = 600/sin(37)

part1 = 600×sin(53)/sin(37) = 796.226893... ft

for the planetarium side triangle we get

part2/sin(61) = 600/sin(29)

part2 = 600×sin(61)/sin(29) = 1,082.428653... ft

the distance between the stadium and the planetarium is

part1 + part2 = 1,878.655546... ft

4 0
2 years ago
There are 5 times as many yellow labs as terriers in the dog park .if there are a total of 18 dogs how many dogs are terriers?
tekilochka [14]
Let t = number of terriers
1 x t = number of total terriers
5 x t = number of yellow labs
1t + 5t = 6t
6t = total number of dogs in the park
6t = 18
t = 18/6
t = 3
there are 3 terriers
8 0
3 years ago
What does 9.6 divided by 0.08
Mila [183]

Answer:

120

Step-by-step explanation:

9.6÷0.08=120

hope this helped

5 0
3 years ago
List 4 rational numbers between-4 and -3?​
lana [24]

-3.1, -3.5, -3.9, -3.8

6 0
4 years ago
Use the arithmetic sequence of numbers 1, 3, 5, 7, 9,.to find the following:
Rasek [7]
a)\\\\
a_{n+1}-a_n=d\\
for\ n=1\\
a_2-a_1=d\\
d=3-1=2\ - difference\ between\ two\ consecutive\ terms\\\\
b)\\
a_n=a_1+(n-1)d\\
n=101\\
a_{101}=1+(101-1)*2\\
a_{101}=1+100*2=200+1=201\\\\
c)\\
Sn=\frac{a_1+a_n}{2}*n\\
n=20\\
a_n=a_{20}=1+(20-1)*2=1+38=39\\
Sn=\frac{1+39}{2}*20=400\ \ Sum\ of\ the\ first\ 20 \ numbers.
6 0
3 years ago
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