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Amiraneli [1.4K]
3 years ago
5

Zinc is used as a coating for steel to protect the steel from environmental corrosion. If a piece of steel is submerged in an el

ectrolysis bath for 24 minutes with a current of 6.5 Amps, how many grams of zinc will be plated out? The molecular weight of Zn is 65.38, and Zn+2 + 2e– → Zn. Question 7 options: A) 3.17 g of Zn B) 1.09 g of Zn C) 6.34 g of Zn D) 12.68 g of Zn
Chemistry
1 answer:
sweet [91]3 years ago
3 0

Answer:

A) 3.17 g of Zn

Explanation:

Let's consider the reduction of Zn(II) that occurs in an electrolysis bath.

Zn⁺²(aq) + 2e⁻ → Zn(s)

We can establish the following relations:

  • 1 min = 60 s
  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant).
  • When 2 moles of electrons circulate, 1 mole of Zn is deposited.
  • The molar mass of Zn is 65.38 g/mol

The mass of Zn deposited under these conditions is:

24min \times \frac{60s}{1min} \times \frac{6.5C}{s} \times \frac{1mol\ e^{-} }{96,468C} \times \frac{1molZn}{2mol\ e^{-}}  \times \frac{65.38g}{1molZn} = 3.17 g

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