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Phoenix [80]
3 years ago
14

Is oxygen soluble in water

Chemistry
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer: Yes

Explanation:

Oxygen is relatively insoluble in water, its solubility being only 264 µM at 25 °C. That explains in part why you (and fish) require dedicated oxygen carriers in your blood to transfer sufficient oxygen around your body.

telo118 [61]3 years ago
4 0

Answer:

Oxygen is relatively insoluble in water

Explanation:

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A mixture of nitrogen and hydrogen gases, at a total pressure of 663 mm Hg, contains 3.46 grams of nitrogen and 0.156 grams of h
STALIN [3.7K]

<u>Answer:</u> The partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

  • <u>For nitrogen gas:</u>

Given mass of nitrogen gas = 3.46 g

Molar mass of nitrogen gas = 28 g/mol

Putting values in above equation, we get:

\text{Moles of nitrogen gas}=\frac{3.46g}{28g/mol}=0.123mol

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 0.156 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in above equation, we get:

\text{Moles of hydrogen gas}=\frac{0.156g}{2g/mol}=0.078mol

Mole fraction of a gas is calculated by using the formula:

\chi_{A}=\frac{n_{A}}{n_{A}+n_{B}}      ......(1)

  • <u>For nitrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{nitrogen gas}}=\frac{0.123}{0.123+0.078}=0.612

  • <u>For hydrogen gas:</u>

Putting values in equation 1, we get:

\chi_{\text{hydrogen gas}}=\frac{0.078}{0.123+0.078}=0.388

The partial pressure of a gas is given by Raoult's law, which is:

p_A=p_T\times \chi_A     ......(2)

where,

p_A = partial pressure of substance A

p_T = total pressure  = 663 mmHg

\chi_A = mole fraction of substance A

  • <u>For nitrogen gas:</u>

p_{\text{Nitrogen gas}}=663mmHg\times 0.612\\\\p_{\text{Nitrogen gas}}=405.76mmHg

  • <u>For hydrogen gas:</u>

p_{\text{Hydrogen gas}}=663mmHg\times 0.388\\\\p_{\text{Hydrogen gas}}=257.24mmHg

Hence, the partial pressure of nitrogen gas is 405.76 mmHg and that of hydrogen gas is 257.24 mmHg

4 0
3 years ago
Explain why you hear a “whoosh” sound when you open a can containing a carbonated drink. Which gas law applies?
Lana71 [14]

Carbonated drinks have the air under pressure so that carbon bubbles are forced into the drink, keeping it carbonated. So when you open a can, the air under pressure in the can comes out of the can at a high speed, making a "whooshing" sound. The gas law that applies to this concept is the Boyle's Law (PV=k or P1V1=P2V2).

6 0
3 years ago
Read 2 more answers
If there is 25.0 L of gas at a temperature of 350C what is the temperature if the volume increases to 75.0L?
Zielflug [23.3K]

Answer:

The new temperature is 1596 C.

Explanation:

Charles's Law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Statistically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Being an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 25 L
  • T1= 350 C= 623 K (being 0 C= 273 K)
  • V2= 75 L
  • T2= ?

Replacing:

\frac{25 L}{623 K} =\frac{75 L}{T2}

Solving:

T2*\frac{25 L}{623 K} =75 L

T2=75 L*\frac{623 K}{25 L}

T2= 1869 K= 1596 C

<u><em>The new temperature is 1596 C.</em></u>

4 0
3 years ago
Besides plants and animals wood and what can be what to release carbon into the air
Alecsey [184]

Humans! They inhale and Exhale Oxygen and Carbon Dioxide.

6 0
3 years ago
What is the mass percentage of carbon in 5.000 G of sucrose
Crank
17) 8.4 / 20 x 100

18) 20 . 0.5150

19) 6,50% because (as you said) the law of definite proportions states that regardless of the amount, a compound is always composed of the same elements in the same proportion by mass
3 0
3 years ago
Read 2 more answers
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