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nasty-shy [4]
3 years ago
6

The groundskeeper of Estofer Park needs to mow 14,623 sq. ft. of grass, He can mow 13 sq. ft. of grass in one minute. How many m

inutes will it take him to mow the entire pare? Give your answer as a mixed number in simplest form.
Pls help
Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
190,099 is your answer for the question
Nonamiya [84]3 years ago
3 0

Answer:

\texttt{Time required to mow = }1124\frac{11}{13}minutes

Step-by-step explanation:

The groundskeeper of Estofer Park needs to mow 14,623 sq. ft.

Total land to be mow = 14,623 sq. ft

He can mow 13 sq. ft. of grass in one minute.

Land mow in one minute = 12 sq. ft.

\texttt{Time required to mow = }\frac{14623}{13}=\frac{13000+1623}{13}=1000+\frac{1623}{13}\\\\\texttt{Time required to mow = }1000+\frac{1300+323}{13}=1000+100+\frac{323}{13}=1100+\frac{260+63}{13}\\\\\texttt{Time required to mow = }1100+20+\frac{63}{13}=1120+\frac{52+11}{13}\\\\\texttt{Time required to mow = }1120+4+\frac{11}{13}=1124\frac{11}{13}minutes

\texttt{Time required to mow = }1124\frac{11}{13}minutes

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Answer:

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Step-by-step explanation:

0,002 \times 0,0004 = 0,0000008

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* You must make sure that you have seven zeros in your decimal.

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6 0
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Derivative of<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B3x%7D%5E%7B2%7D%20-%202x%20-%201%20%7D%7B%20%7Bx%7D%5E%7B2
Anastaziya [24]

Answer:

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Step-by-step explanation:

we would like to figure out the derivative of the following:

\displaystyle  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

to do so, let,

\displaystyle y =  \frac{ { 3x }^{2} - 2x - 1 }{ {x}^{2} }

By simplifying we acquire:

\displaystyle y =  3 -  \frac{2}{x}  -  \frac{1}{ {x}^{2} }

use law of exponent which yields:

\displaystyle y =  3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} }

take derivative in both sides:

\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  (3 -  2 {x}^{ - 1}  -   { {x}^{  - 2} } )

use sum derivation rule which yields:

\rm\displaystyle  \frac{dy}{dx} =  \frac{d}{dx}  3 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

By constant derivation we acquire:

\rm\displaystyle  \frac{dy}{dx} =  0 -   \frac{d}{dx} 2 {x}^{ - 1}  -     \frac{d}{dx} {x}^{  - 2}

use exponent rule of derivation which yields:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ - 1 -1} ) -     ( - 2 {x}^{  - 2 - 1} )

simplify exponent:

\rm\displaystyle  \frac{dy}{dx} =  0 -   ( - 2 {x}^{ -2} ) -     ( - 2 {x}^{  - 3} )

two negatives make positive so,

\displaystyle  \frac{dy}{dx} =   2 {x}^{ -2} +      2 {x}^{  - 3}

<h3>further simplification if needed:</h3>

by law of exponent we acquire:

\displaystyle  \frac{dy}{dx} =   \frac{2 }{x^2}+       \frac{2}{x^3}

simplify addition:

\displaystyle  \frac{dy}{dx} =    \frac{2x + 2}{x^3}

and we are done!

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Vadim26 [7]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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In this question:

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