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3 years ago

Most of earths fresh water is in glaciers True or false PEASE HELPP

Chemistry

2 answers:

Sati [7]3 years ago

4 0

Answer:

True

Explanation:

Flauer [41]3 years ago

3 0

Answer is TRUE!!!

Explanation:
Most of oceans are salt water.
BUT lakes, ponds, springs, glaciers, etc are fresh water

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help plz Which list is in order from smaller to larger sediment particles? A. sand, silt, clay B. clay, silt, sand C. silt, sand

MariettaO [177]

Answer : The correct option is B (clay, slit, sand).

Explanation :

Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.

Particle size range of the sand = 2.00 -0.05 mm

Particle size range of the slit = 0.05 -0.002 mm

Particle size range of the sand = less than 0.002 mm

Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.

Therefore, the order from smaller to larger sediment particles is

Clay > Slit > Sand

5 0

3 years ago

When you exercise strenuously, your body produces excess heat. Describe what your body does to help prevent your temperature fro

VARVARA [1.3K]

Answer:

Your body can cool itself by sweating. When sweat evaporates, it lowers your temperature

Explanation:

7 0

2 years ago

Read 2 more answers

Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y

Anna [14]

Answer:

No hoblo englas

Explanation:

7 0

3 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

Contact [7]

Answer: The total volume of the gaseous products is 1044.29 L

Explanation:

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = $\frac{1}{22.4}\times 116=5.18mol$ of butane

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

For carbon dioxide:

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = $\frac{8}{2}\times 5.18=20.72mol$ of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

For water vapor:

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = $\frac{10}{2}\times 5.18=25.9mol$ of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0

3 years ago

Balance each of these equations.

mafiozo [28]

The answer I would choose is the third one

4 0

3 years ago