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3 years ago

Most of earths fresh water is in glaciers True or false PEASE HELPP

Chemistry

2 answers:

Sati [7]3 years ago

4 0

Answer:

True

Explanation:

Flauer [41]3 years ago

3 0

Answer is TRUE!!!

Explanation:
Most of oceans are salt water.
BUT lakes, ponds, springs, glaciers, etc are fresh water

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You have 0.5 l of air at 203 k in an expandable container at constant pressure. you heat the container to 273 k. what is the new

Leviafan [203]

0.593 L. V1/T1 = V2/T2

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3 years ago

A solution has a pH of 11.8. What is the pOH?

amid [387]

Answer:

pOH is 2.2

Explanation:

The pH scale goes from 0 to 14. As such, the pH and the pOH add up to 14. Subtract your pH from 14 to get your answer.

14 - 11.8 = 2.2

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3 years ago

Hydrogen bonds within liquid water are attractions between protons and hydroxide ions. are dipole-dipole attractions. are ion-in

barxatty [35]

Answer:

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3 years ago

2.600 * 10 ^ - 5 * 6.100 * 10 ^ - 5 Express in scientific notation

Anna [14]

Answer:

hope its help you

Explanation:

2.600 × 10^-5 × 6.100 × 10^-5 = 1.586 × 10-9

3 0

3 years ago

Calcium nitrate and ammonium fluoride react to form calcium fluoride, dinitrogen monoxide, and water vapor. How many grams of di

pychu [463]

Answer:

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant. Explanation:

$Ca(NO_3)_2(aq)+2NH_4F(aq)\rightarrow CaF_2(aq)+2N_2O(g)+4H_2O(g)$

Moles of calcium nitrate = $\frac{31.3 g}{164 g/mol}=0.1908 mol$

Moles of ammonium fluoride = $\frac{38.7 g}{37 g/mol}=1.046 mol$

According to reaction , 2 moles of ammonium fluoride reacts with 1 mole of calcium nitrate.

Then 1.046 moles of ammonium fluoride will react with :

$\frac{1}{2}\times 1.046 mol=0.523 mol$ calcium nitarte .

This means that ammonium fluoride is in excess amount and calcium nitrate is in limiting amount.

Hence, calcium nitrate is a limiting reactant.

So, amount of dinitrogen monoxide will depend upon moles of calcium nitrate.

So, according to reaction , 1 mole of calcium nitarte gives 2 moles of dinitrogen monoxide gas .

Then 0.1908 moles of calcium nitrate will give:

$\frac{2}{1}\times 0.1908 mol=0.3816 mol$ of dinitrogen monoxide gas.

Mass of 0.03816 moles of dinitrogen monoxide gas:

0.03816 mol × 44 g/mol = 16.79 g

16.79 grams of dinitrogen monoxide are present after 31.3 g of calcium nitrate and 38.7 g of ammonium fluoride react completely. And calcium nitrate is a limiting reactant.

8 0

3 years ago