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2 years ago

Most of earths fresh water is in glaciers True or false PEASE HELPP

Chemistry

2 answers:

Sati [7]2 years ago

4 0

Answer:

True

Explanation:

Flauer [41]2 years ago

3 0

Answer is TRUE!!!

Explanation:
Most of oceans are salt water.
BUT lakes, ponds, springs, glaciers, etc are fresh water

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What are abiotic factors of the ecosystem

dalvyx [7]

Answer:

Abiotic factors are the non-living components of the ecosystem, including its chemical and physical factors.

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2 years ago

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Why is water able to stick to the side of the glass?

Ira Lisetskai [31]

The answer is surface tension

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3 years ago

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What is the pH of a solution made by mixing 200 mL of 0.025M HCl and 150 mL of 0.050 M HCl?

seraphim [82]

Answer:

The answer to your question is pH = 1.45

Explanation:

Data

pH = ?

Volume 1 = 200 ml

[HCl] 1 = 0.025 M

Volume 2 = 150 ml

[HCl] 2 = 0.050 M

Process

1.- Calculate the number of moles of each solution

Solution 1

Molarity = moles / volume

-Solve for moles

moles = 0.025 x 0.2

result

moles = 0.005

Solution 2

moles = 0.050 x 0.15

-result

moles = 0.0075

2.- Sum up the number of moles

Total moles = 0.005 + 0.0075

= 0.0125

3.- Sum up the volume

total volume = 200 + 150

350 ml or 0.35 l

4.- Calculate the final concentration

Molarity = 0.0125 / 0.35

= 0.0357

5.- Calculate the pH

pH = -log [H⁺]

-Substitution

pH = -log[0.0357]

-Result

pH = 1.45

8 0

3 years ago

How many grams of drug powder would you need to weigh to prepare 32ml of a suspension that should have a strength of 20mg/ml?

butalik [34]

15 grams for the drug powder

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2 years ago

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How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

7 0

3 years ago