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oksian1 [2.3K]
3 years ago
15

Most of earths fresh water is in glaciers True or false PEASE HELPP

Chemistry
2 answers:
Sati [7]3 years ago
4 0

Answer:

True

Explanation:

Flauer [41]3 years ago
3 0
Answer is TRUE!!!

Explanation:
Most of oceans are salt water.
BUT lakes, ponds, springs, glaciers, etc are fresh water
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help plz Which list is in order from smaller to larger sediment particles? A. sand, silt, clay B. clay, silt, sand C. silt, sand
MariettaO [177]

Answer : The correct option is B (clay, slit, sand).

Explanation :

Soil particles are of three types : Sand, Slit and clay. Most of the soils particles are made up of a combination of sand, slit and clay.

Particle size range of the sand = 2.00 -0.05 mm

Particle size range of the slit = 0.05 -0.002 mm

Particle size range of the sand = less than 0.002 mm

Sand is the largest soil particle, clay is the smallest soil particle and slit particle is present in between the sand & clay particle.

Therefore, the order from smaller to larger sediment particles is

Clay > Slit > Sand

5 0
3 years ago
When you exercise strenuously, your body produces excess heat. Describe what your body does to help prevent your temperature fro
VARVARA [1.3K]

Answer:

Your body can cool itself by sweating. When sweat evaporates, it lowers your temperature

Explanation:

7 0
2 years ago
Read 2 more answers
Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y
Anna [14]

Answer:

No hoblo englas

Explanation:

7 0
2 years ago
What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin
Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = \frac{1}{22.4}\times 116=5.18mol of butane

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = \frac{8}{2}\times 5.18=20.72mol of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

  • <u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = \frac{10}{2}\times 5.18=25.9mol of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0
3 years ago
Balance each of these equations.
mafiozo [28]
The answer I would choose is the third one
4 0
3 years ago
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