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IgorLugansk [536]
3 years ago
5

PLZ HELP AHHHHHHHHHHHHHHHHHHHHHHSimplify 3^4+(7^2−2^4)

Mathematics
1 answer:
Leokris [45]3 years ago
8 0

3 \times 3 \times 3 \times 3 + (7 \times 7 - 2 \times 2 \times 2 \times 2)
That's all you need to do
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Evaluate a+b for a =34 and b=-6
Digiron [165]

Question

evaluate a+b for a =34 and b=-6

a + b =

34 + (-6) =

34 - 6 =

28

5 0
3 years ago
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Are the given lines parallel? Explain <br> X=-1, and y=2
german
No they would be intersecting. x=-1 is a vertical line down the x axis on -1. y=2 is a horizontal line at 2 on the y axis.
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3 years ago
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irina [24]

the answer is c...........

7 0
3 years ago
On a coordinate plane, a parabola opens up. Solid circles appear on the parabola at (negative 6, 6), (negative 4. 5, 2. 25), (ne
iragen [17]

The rate of change for the interval between –6 and –3 on the x-axis is -2.

<h2>Given that</h2>

On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (-6, 6), (-4. 5, 2. 25), (-3, 0), (-1. 5, -0. 75), (0, 0), (1,5, 2. 25), and (3, 6).

<h3>We have to determine</h3>

Which is the rate of change for the interval between –6 and –3 on the x-axis?

<h3>According to the question</h3>

On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (-6, 6), (-4. 5, 2. 25), (-3, 0), (-1. 5, -0. 75), (0, 0), (1,5, 2. 25), and (3, 6).

The rate of change for the interval between x = -6 and x = -3 is simply asking you for the slope of the line that connects these 2 coordinates.

Then,

The rate of change for the interval between –6 and –3 on the x-axis is,

\rm Rate \ of \ change = \dfrac{y_2-y_1}{x_2-x_1}\\&#10;\\&#10; Rate \ of \ change = \dfrac{-6-0}{-3-(-6)}\\&#10;\\&#10; Rate \ of \ change =\dfrac{-6}{3}\\&#10;\\&#10; Rate \ of \ change =-2

Hence, the rate of change for the interval between –6 and –3 on the x-axis is -2.

To know more about Parabola click the link given below.

brainly.com/question/16549411

7 0
3 years ago
Tutoring Services: The Community College Survey of Student Engagement reports that 46% of the students surveyed rarely or never
gulaghasi [49]

Answer: Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

Step-by-step explanation:

Given : The proportion of community college students never use tutoring services available at their college: p= 0.40

Mean of the sampling distribution of sample proportions  = p = 0.40

Since sample size : n= 500

Standard error = \sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.40(1-0.40)}{500}}

=\sqrt{\dfrac{0.24}{500}}

=\sqrt{0.00048}=0.0219

Hence, Mean = 0.40 and  standard error = 0.0219 of the sampling distribution of sample proportions.

3 0
3 years ago
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