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Goryan [66]
3 years ago
8

What is the horizontal distance between these two points (3,4) and (8,4)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:

5 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

 

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

 

Where

(x_1,y_1) = (3,4)

(x_2,y_2) = (8,4)

 

Replacing these values in the distance formula

D =\sqrt{(3-8)^2+(4-4)^2}

D =\sqrt{(-5)^2+(0)^2}

D =\sqrt{25}

D= 5

 

Hence the Distance is 5 units

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Find the slope of the line that goes through each pair of points. (-1,7) and (5,7)
Georgia [21]

Answer:

0

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-7)/(5-(-1))

m=0/(5+1)

m=0/6

m=0

5 0
3 years ago
Theresa pays $9.56 for 4 pounds of tomatoes. What is the cost of 1 pound of tomatoes?
photoshop1234 [79]

Answer:

$2.39

Step-by-step explanation:

to find the cost of 1 pound , divide the cost of 4 pounds by 4

$9.56 ÷ 4 = $2.39

8 0
2 years ago
-4x+y=23 and 4x-9y=-15
astra-53 [7]

Answer:  x= -6; y= -1

Step-by-step explanation:

-4x + y = 23

4x - 9y = - 15

-4x + y = 23

      y = 23 + 4x     [Add 4x to both side]

4x - 9(23 + 4x) = - 15

4x - 207 - 36x = - 15

-32x - 207 = -15

-32x = 192             [Add 207 to both side]

    x = -6                [Divide -32 from both side]

-4x + y = 23

-4(-6) + y = 23          [Plug in -6 for x]

24 + y = 23              [Subtract 24 from both side]

       y = -1

5 0
3 years ago
Which points on the curve of x^2 - xy - y^2 = 5 have vertical tangent lines?
algol [13]

We need to differentiate this with respect to x to see if we can find an expression for the derivative of y at various points.  That will be the slope of the tangent to the curve.  Then we want to see where that derivative might be infinite -- i.e., where the tangent is vertical.

 

It's not written as a function, but it can still be differentiated using the chain rule:

 

x2 + xy + y2 = 3

(2x) + (x dy/dx + y dx/dx) + (2y dy/dx) = 0

 

(I used parentheses to show the differentiation of each term in the original equation.)

 

2x + x dy/dx + y + 2y dy/dx = 0

2x + y = -x dy/dx - 2y dy/dx

2x + y = dy/dx (-x -2y)

-(2x + y)/(x + 2y) = dy/dx

 

We have the derivative of y, but it's defined partly in terms of y itself.  That's OK.  Let's go on...

 

So where would the slope be infinite?  That would happen when x + 2y = 0, or y = -x/2

 

Let's plug that in for y in the original equation to find points where that's the case.

 

x2 + xy + y2 = 3

x2 + x(-x/2) + (-x/2)2 = 3

x2 - x2/2 + x2/4 = 3

3x2 / 4 = 3

x2 = 4

x = ±2

 

So we have two x values where the tangent might be vertical.  Let's plug them into the equation and see what the y values are.  First x = 2...

 

x2 + xy + y2 = 3

4 + 2y + y2 = 3

y2 + 2y + 1 = 0

(y + 1)2 = 0

y = -1

 

So at the point (2, -1) the tangent is vertical.

 

Now try x = -2...

 

x2 + xy + y2 = 3

4 - 2y + y2 = 3

y2 - 2y + 1 =0

(y - 1)2 = 0

y = 1

 

So at the point (-2, 1) the tangent is vertical.

8 0
2 years ago
Explain the steps you would take to write 36/10 as a decimal
kherson [118]
You just have to make 36/10 into 3 6/10. After that, it would become 3.6
4 0
3 years ago
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