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jeyben [28]
3 years ago
7

Describe the motion of an object that has an acceleration of 0 mi./s squared

Physics
1 answer:
miskamm [114]3 years ago
5 0
The object does not move.
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3. What is the velocity of a wave that has a frequency of 750 Hz and a wavelength of 45.7 cm?
sweet-ann [11.9K]

Explanation:

v=(750)(45.7)

v=34275

or

v=(750)(0.457)

v=342.75

3 0
3 years ago
You need to remove a broken light bulb from a lamp. without a pair of gloves, you are likely to cut yourself on the jagged glass
mojhsa [17]
<span>You have just demonstrated an insight learning. Internal insight occurs if one learned a new way without the help of environmental factors. In here, what the person initially learned that if one saw a broken light bulb from a lamp, he can be cut through the jagged glass if one does not wear a pair of gloves. And maybe because at the moment, the person could not find one, he felt using a cut potato to pick up the pieces of the broken lamp. This is a demonstration of insight learning. The person found a way to pick up the pieces of the broken lamp by using his instinct at the moment. The person is not influenced by an outside source to tell him to use a potato. </span>
5 0
3 years ago
A car is moving 5.82M/S when it accelerates at 2.35M/S^2for 3.25S. What is its final velocity?
rodikova [14]

Answer:

Explanation:

vf=vi+at

vi=5.82 m/s

a=2.35 m/s2

t=3.25 s

vf=5.82+2.35*3.25

vf=5.82+7.64

vf=13.46

3 0
3 years ago
When the distance between two masses is doubled, the gravitational attraction between
mrs_skeptik [129]

The new gravitational attraction will be 1/4 as much

Explanation:

The magnitude of the gravitational force between two objects is given by

F=G\frac{m_1 m_2}{r^2}

where

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between them

In this problem, the original force between the two objects is F, when they are separated by a distance r.

Later, the distance between the two objects is doubled, so the new distance is

r'=2r

Therefore, the new force will be

F'=G\frac{m_1 m_2}{(2r)^2}=\frac{1}{4}(\frac{Gm_1 m_2}{r^2})=\frac{F}{4}

Therefore, the new force will be one-fourth as much.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

5 0
3 years ago
An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?
NemiM [27]

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

7 0
3 years ago
Read 2 more answers
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