The ratio of time of flight for inelastic collision to elastic collision is 1:2
The given parameters;
- <em>mass of the bullet, = m₁</em>
- <em>mass of the block, = m₂</em>
- <em>initial velocity of the bullet, = u₁</em>
- <em>initial velocity of the block, = u₂</em>
Considering inelastic collision, the final velocity of the system is calculated as;
The time of motion of the system form top of the table is calculated as;
Considering elastic collision, the final velocity of the system is calculated as;
Apply one-directional velocity
Substitute the value of 
into the above equation;
where;
is the final velocity of the block after collision
<em>Since the</em><em> bullet bounces off</em><em>, we assume that </em><em>only the block fell </em><em>to the ground from the table.</em>
The time of motion of the block is calculated as follows;
The ratio of time of flight for inelastic collision to elastic collision is calculated as follows;
Learn more about elastic and inelastic collision here: brainly.com/question/7694106
Answer:
Resultant displacement = 38.58 miles at an angle of 23.57° north of west.
Explanation:
Let north represent positive y direction and east represent positive x direction. Unit vector along x direction is represented by i and vector along unit vector along y direction is represented by j
Initial displacement = 17 miles north = 17 j miles
Final displacement = 24 miles at an angle of 40° west of north = 24 miles at an angle of 130° to positive x -axis
= (24 cos 130 i + 24 sin 130 j )
= (-15.43 i + 18.36 j ) miles
Total displacement = 17 j + (-15.43 i + 18.36 j) = -15.43 i + 35.36 j
Magnitude of displacement 
Angle to positive x -axis = tan⁻¹(35.36/-15.43) = 113.57°
Resultant displacement = 38.58 miles at an angle of 23.57° west of north.
Answer:
answer is C
Explanation:
acceleration is rate of changing velocity in a time
Answer: a. 667N
b. 665N
c. 54.5N
Explanation:
a) on the surface of the earth
W = mg
W = 68 × 9.81
= 667N
b) at the top of Everest (8848 m above sea level).
W =mg × R²/(R + H)²
W = 667 × [6378²/(6378 + 8.848)²
W = 665N
c) has 2 1/2 times the radius of the earth
W = mg × R²/(R + H)²
W = 667 × R²/(R + 2.5R)²
W = 54.5N
