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Sonja [21]
3 years ago
14

А

Physics
1 answer:
bagirrra123 [75]3 years ago
7 0

Explanation:

The reading on the scale is

W = m(g + a)

= (77 kg)(9.8 m/s^2 + 2 m/s^2)

= 908.6 N

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Nancy walks 100 m west and then 60 m east. What is Nancy's displacement?
babunello [35]

Answer:

40m to the East

Explanation:

Displacement is the distance moved in a specific direction. When writing the displacement value of a moving body, the direction must be put in the description.

Displacement takes into account the start and finish position of a body.

                                                 100m

Start         --------------------------------------------------------------  →

                                                               60m

                                       Final ←----------------------------------

Displacement  = 100m  - 60m  = 40m

 Therefore, the displacement is 40m due east

8 0
3 years ago
If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwi
Anastaziya [24]

Answer:

The magnitude  of the electric field is 5.1 \times 10^{11}  \frac{N}{C}

Explanation:

Given:

Charge of electron q = 1.6 \times 10^{-19}C

Separation between two charges r = 5.3 \times 10^{-11} m

For finding the magnitude of the electric field,

   E= \frac{kq}{r^{2} }

Where k = 9 \times 10^{9}

   E = \frac{9 \times 10^{9} \times 1.6 \times 10^{-19} }{(5.3 \times 10^{-11} )^{2} }

   E = 5.1 \times 10^{11} \frac{N}{C}

Therefore, the magnitude  of the electric field is 5.1 \times 10^{11}  \frac{N}{C}

5 0
4 years ago
A 1800 kg car moving south at 17.5 m/s collide with a 2800 kg car moving north. The cars stick together and move as a unit after
weqwewe [10]

Answer:

   v₀₂ = -2.67 m / s

Explanation:

Let's use the conservation of the moment, for this we define a system formed by the two cars.

Consider the north direction as positive and the subscript 1 will be used for car 1 and the subscript 2 for the second car

Initial instant. Before the crash

          p₀ = -m₁ v₀₁ + m₂ v₀₂

Final moment. Right after the crash

          p_f = (m₁ + m₂) v

           p₀ = p_f

           -m₁ v_{o1} + m₂ v_{o2} = (m₁ + m2) v_{f}

         v₀₂ = \frac{(m_1 +m_2) v }{m_2}+  \frac{m_1 v_{o1}  }{m_{1} }

 

let's calculate

          v₀₂ = \frac{(1800 +2800) 5.22 + 1800 (-17.5)}{2800}

          v₀₂ = -2.67 m / s

the negative sign indicates that the carriage moves in the opposite direction of the temperies

8 0
3 years ago
Describe what happens when u mix hot water with cold
svetoff [14.1K]
The hot immediately increase the temperature of the cold water until they both reach equilibrium state.
6 0
3 years ago
A stereo speaker is placed between two observers who are 40 m apart, along the line connecting them. if one observer records an
Nadya [2.5K]

The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

            β = 10 log\frac{I_a}{I_o}

where I₀ = 1 \times 10^{-12}  W / m²

             I_a = I_b \times 10 ^{ \frac{\beta}{10} }

             I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }

             I_a = 2.51 \times 10 ^{-6} W / m²

Similarly for Observer b I_b = 3.16 \times 10 ^ {-4}

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of ​​a sphere is

A= 4\pi \times r^2

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

            I_a (35 -x) ^2 = I_b x^2

after solving the above equation we get  x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

To know more about intensity of sound with the given link

#SPJ4

6 0
1 year ago
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