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Sonja [21]
3 years ago
14

А

Physics
1 answer:
bagirrra123 [75]3 years ago
7 0

Explanation:

The reading on the scale is

W = m(g + a)

= (77 kg)(9.8 m/s^2 + 2 m/s^2)

= 908.6 N

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Hi.
zhenek [66]

Answer: Units: C, T and Variables: <em>c, C, t, T</em>

(a) C is the unit of charge Coulomb, (e) T is the unit of magnetic field strength Tesla.

In physics, units are written straight and variables are written in italics. Various italic symbols are used for various quantities like <em>t </em>for time, <em>T</em> for temperature, <em>c</em> for any constant and <em>C</em> for curie constant.

4 0
3 years ago
Read 2 more answers
A pilot flies in a straight path for 1 hour 30 minutes. She then makes a course correction, heading 45 degrees to the right of h
mrs_skeptik [129]

Answer:

1199 miles

Explanation:

1 hour 30 minutes = 1 + 30/60 = 1.5 hours

2 hours 15 minutes = 2 + 15/60 = 2.25 hours

The distance she flew in the 1st segment is:

1.5*345 = 517.5 miles

The distance she flew in the 2nd segment is:

2.25 * 345 = 776.25 miles

Since the 2nd segment is 45 degree with respect to the 1st segment, this means that she has flown

776.25 * cos(45) = 549 miles in-line with the 1st segment and

776.25* sin(45) = 549 miles perpendicular to the 1st segment:

So the distance from the end to her starting position is

\sqrt{(517.5 + 549)^2 + 549^2} = 1199 miles

4 0
3 years ago
How are steam powered boats different from sailboats
Alex
Steam powered boats run from an engine, using power, gears, and cranks to function.

Sailboats use no engine and rely on winds to move and change the direction of the boat. 
3 0
3 years ago
Read 2 more answers
Two objects are placed 3 meters apart. If they were moved, at what distance would the NEW gravitational force be about 1/4 of th
gayaneshka [121]

Answer:

3/4

Explanation:

3 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
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