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Elenna [48]
3 years ago
10

A 1.803 g sample of gypsum, a hydrated salt of calcium sulfate, CaSO4 is heated at a temperature greater than 170 degree Celsius

in a crucible until a constant mass is reached. The mass of anhydrous CaSO4 salt is 1.426g. Calculate the percent by mass of water in the hydrated calcium sulfate salt.
Chemistry
1 answer:
brilliants [131]3 years ago
6 0

Answer:

20.91% of the hydrated calcium sulfate salt is water

Explanation:

<u>Step1</u> : Calculate the mass of H2O that evaporated

A hydrated salt has a mass of 1.803g. After heating at 170° C, this means water will evaporate, the mass of the salt is 1.426g

The difference is water that evaporated.

⇒Mass H2O of hydration =1.803 g - 1.426g g = 0.377 g H2O

<u>Step 2</u>: Calculate the % of water in the hydrated calcium sulfate salt

⇒ mass of H2O = 0.377g

⇒ mass of calcium sulfate salt = 1.803g

⇒ % water in the calcium sulfate salt = (0.377 / 1.803) x 100% = 20.91%

20.91% of the hydrated calcium sulfate salt is water

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<em />

That means the option with the higher m*i will be the solution with the highest boiling point:

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d. C₆H₁₂O₆ has i = 1:

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The solution with highest boiling point is:

<h3>c. 0.1 M Ga₂(SO₄)₃</h3>
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