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Margarita [4]
3 years ago
15

How can operators avoid damaging Submersed Aquatic Vegetation (SAV) beds that are usually found in shallow areas of water?

Physics
1 answer:
Ivan3 years ago
4 0
Operators can avoid damaging SAV's by only operating at high tides, and watch where they are going, because past scientific studies have shown that propellers from machines are known to damage existing SAV's<span />
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ASAP WILL GIVE BRAINLIEST!!!
Oksana_A [137]

Answer:

<em>The change in momentum of the car is 3575 Kg.m/s</em>

Explanation:

<u>Impulse and Momentum</u>

The impulse (J) experienced by the object equals the change in momentum of the object (Δp).

The formula that represents the above statement is:

J = Δp

The impulse is calculated as

J = F.t

Where F is the applied force and t is the time.

The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:

J = 6500 * 0.55

J = 3575 Kg.m/s

The change in momentum of the car is:

\Delta p= J = 3575\ Kg.m/s

The change in momentum of the car is 3575 Kg.m/s

5 0
3 years ago
3. If a certain quantity of gas has a volume of 30 cm3 at a pressure of 1 × 105 Pa, what is its volume when the pressure is
arlik [135]

We know that:

                             P_{1}V_{1}= P_{2}V_{2}               .......(1)

Given at P_{1}=30cm^3 , V_{1}=10^5Pa

a)

When P_{2}=2*10^5Pa , V_2=?

Using equation (1)

                                    30*10^5=2*10^5*V_2

                                     V_2=30/2=15cm^3

b)

When P_2=5*10^5Pa, V_2=?

using equation (1)

                                     30*10^5=5*10^5*V_2

                                    V_2=30/5=6cm^3

5 0
3 years ago
Can anybody write a short poem about friction
Luden [163]
Answer:

you will be the clouds
and I will be the sky.
you will be the ocean
and I will be the shore.
you will be the trees
and I will be the wind.

whatever we are, you and I will always collide.

There you go! Let me know if it helped.
:)
8 0
2 years ago
A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
Oduvanchick [21]

To solve this problem it is necessary to apply the concepts based on Newton's second law and the Centripetal Force.

That is to say,

F_c = F_w

Where,

F_c =Centripetal Force

F_w =Weight Force

Expanding the terms we have to,

mg = \frac{mv^2}{r}

gr = v^2

v = \sqrt{gr}

Where,

r = Radius

g = Gravity

v = Velocity

Replacing with our values we have

v = \sqrt{(9.8)(11.8)}

v = 10.75m/s

Therefore the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top is 10.75m/s

5 0
4 years ago
How is a charged object created?
Sever21 [200]

Answer:

Charges are transferred from one object to another.

Explanation:

The charges from one object to another are sharing there energy.

5 0
3 years ago
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