Answer:
A ) Find the direct runoff depth; d =V A 22,698 _ 2.25x106 =0.01m =1cm The above result shows that the given hydrograph qualifies as a unit hydrograph. .
Explanation:
Brainlyist
Aha! This is a fun question, likely AP Physics 1 if I'm not mistaken. This is how you solve it, you need the following equation.
Now on this question you don't need to actually use the mass and diameter of the earth as we are only
looking at the
factor of how much your weight would change, so you can just plug in some random numbers for the mass and radius. In my case I will use the original radius as being
2 meters and the original mass of the earth as being
20kg. You can actually just omit the mass of your body and the gravitational constant isn't necessary to be multiplied by because they will remain the same in both scenarios.
Original weight:
So the original weight in this circumstance is 5N. Now then if we double the mass to
40kg and the radius to
4m you will have the following.
So the original weight was 5N and after doubling the mass and radius the weight reduced to 2.5N. This means the factor which your weight would change by is .5 or decrease by 1/2.
I hope this helps you :) You can ask me if you have any additional physics questions.
Answer: Radio signals sent through space
Explanation:
>Radio signals are electromagnetic signals which can travel through space even in vacuum where no air is absent . Radio signals carry energy in the form of electromagnetic wave .
>Thunder heard from many miles away is due to propagation of sound wave in the air or atmosphere . The sound wave carries energy in the form of mechanical energy which can not propagate in vacuum and requires a medium .
>When nuclei of atoms split into parts they fly away from each other with some speed carrying kinetic energy which is a part of mechanical energy .
Thus mechanical energy is involved in all the given examples expect the case of radio signals sent through space.
HELPPPPPPPPPPPPPPPPPPPPPPP HELPPPPPPPPPPPPPPPPPPPPPPP and a few others i
W=ΔKE , W=-5000j
KEinitial=(1/2)mv² , KEfinal=0j
ΔKE=-(1/2)mv²
-5000=-(1/2)(100kg)v²
v=10 m/s