One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What
2 answers:
Let us say there are x number of candies .
For first student,
He ate 3/20 of all candies, so 3/20 (x)
He also ate 1.2 lb of candies.
Total candies first student ate = (3/20) x +1.2
Second student ate 3/5 of all candies that is (3/5)x
He also ate 0.3 lb of candies.
Total candies second student ate = (3/5)x +0.3
Since total candies for both will be same, so equating the two expressions
x=2
So there are 2 lb of candies in total.
First student ate = 0.3 +1.2 = 1.5lb of candies.
Second student ate = 1.5 lb of candies
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Answer:
(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.
Step-by-step explanation:
Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.
This implies that boxes are in multiples of 12
i.e. 12, or 24, or 36 or....
Let us say this as 12m for m an integer
Now additional boxes arrived =60
Total number of boxes now =
This when arranged in stacks of 14,nothing left out
Or this is multiple of 14
for some positive integer n.
By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.
So we say originally 24 boxes were there now 84 boxes there.
Hence both options are right.
(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.