One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What
2 answers:
Let us say there are x number of candies .
For first student,
He ate 3/20 of all candies, so 3/20 (x)
He also ate 1.2 lb of candies.
Total candies first student ate = (3/20) x +1.2
Second student ate 3/5 of all candies that is (3/5)x
He also ate 0.3 lb of candies.
Total candies second student ate = (3/5)x +0.3
Since total candies for both will be same, so equating the two expressions
x=2
So there are 2 lb of candies in total.
First student ate = 0.3 +1.2 = 1.5lb of candies.
Second student ate = 1.5 lb of candies
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By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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