One student ate 3/20 of all candies and another 1.2 lb. The second student ate 3/5 of the candies and the remaining 0.3 lb. What
2 answers:
Let us say there are x number of candies .
For first student,
He ate 3/20 of all candies, so 3/20 (x)
He also ate 1.2 lb of candies.
Total candies first student ate = (3/20) x +1.2
Second student ate 3/5 of all candies that is (3/5)x
He also ate 0.3 lb of candies.
Total candies second student ate = (3/5)x +0.3
Since total candies for both will be same, so equating the two expressions
x=2
So there are 2 lb of candies in total.
First student ate = 0.3 +1.2 = 1.5lb of candies.
Second student ate = 1.5 lb of candies
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The answer is the option A 9.9 grams
because the balance is accurate to the nearest 1/10 gram; thus, the <span>highest level of accuracy appropriate to the limitations of the balance is 0.10 gram (1/10)</span>
Step-by-step explanation:
use CAH method (Cos angle = adjacent/hypotenuse)
Given adjacent = 5
Hypotenuse = 12,