Ask question

Ask question

All categories

3 years ago

9

I really need help with my science homework

2 answers:

Kamila [148]3 years ago

8 0

SYMBOL, GROUP, PERIOD
He, Nobel Gas, 2
C, Nonmetal, 6
NA, Alkali metals, 11
S, non-metal, 16
Sn, Post-transition metal, 50
Ca, Alkali metals, 20
Li, alkali metals, 3
F, nonmetal, 9
K, alkali metal, 19
Mn, Transition metals, 25
P, nonmetal, 15
That's all I can do. Sorry. Its in order from top.

LuckyWell [14K]3 years ago

5 0

I can help, pm me and i will help you on there if that's alright?

You might be interested in

Read the hypotheses below, then answer the questions.

stiks02 [169]

A the type of soil the tulip receive- with or without fertilizer

5 0

2 years ago

Read 2 more answers

gold(iii) chloride reacts with Antimony(III) oxide and water to produce Gold Antimony(V) oxide and Hydrochloric acid balanced eq

zhuklara [117]

Balanced equation below

5 0

3 years ago

Why aluminum in 1820 had more value than gold

bonufazy [111]

Answer:

Aluminum had more value than gold in the 1820s, because it was harder to obtain. Hope this helped :)

4 0

2 years ago

a fraction collected during distillation ethanol-water what is the mass of ethanol that is present in this fraction

AURORKA [14]

Answer:

80 kg

Explanation:

because the liquid with high boiling point is going to be collected the first

4 0

1 year ago

A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree

lions [1.4K]

Answer:

The new temperature of the water bath 32.0°C.

Explanation:

Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)

Initial temperature of the water = $T_1=33.9^oC=33.9+273K=306.9 K$

Final temperature of the water = $T_2$

Specific heat capacity of water under these conditions = c = 4.18 J/gK

Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J

( 1kJ=1000 J)

$Q=m\times c\times \Delta T=m\times c\times (T_2-T_1)$

$-69.0\times 1000 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$-69,000.0 J=8100 g\times 4.18 J/g K\times (T_2-306.9 K)$

$T_2=304.86 K=304.86 -273^oC=31.86^oC\approx 32.0^oC$

The new temperature of the water bath 32.0°C.

5 0

3 years ago