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ycow [4]
3 years ago
6

gypsum is insoluble in water. you are asked to purify a sample of gypsum that is contaminated with a soluble salt.

Chemistry
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

a. The apparatus required to purify gypsum sample are: Bunsen burner, beaker, Filter Funnel, stirring rod, the filter paper.

b. Gypsum is a sulfate mineral that is made up of calcium sulfate dihydrate. Step-by-step instruction to purify gypsum sample is as follows:

1. Add water to the gypsum sample in a beaker.

2. Use the stirring rod to mix the mixture well.

3. Filter off the excess solid from the mixture using the filter paper and filter funnel.

4. Put the filtered mixture over the bunsen burner and evaporate the excess water from the mixture.

5. Allow the hot liquid to cool down and filter it again through the filter paper to get the pure gypsum.

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blondinia [14]

Answer:

1.64 moles O₂

Explanation:

Part A:

Remember 1 mole of particles = 6.02 x 10²³ particles

So, the question becomes, how many  '6.02 x 10²³'s are there in 9.88 x 10²³ molecules of O₂?

This implies a division of given number of particles by 6.02 x 10²³ particles/mole.

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Part B needs an equation (usually a combustion of a hydrocarbon).

7 0
2 years ago
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krek1111 [17]
A + BC  ---> AB + C
So here one reactant (A) is accepting a group which is being given by another compound (BC) however the A is not giving any group / element or ion
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The element Ca accepts OH- and H2O loses the same group to form new element H2
So the correct answer is
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5 0
3 years ago
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Brrunno [24]

Answer:

Loses

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4 0
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