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pychu [463]
2 years ago
12

An ice cube absorbs 353 cal of

Chemistry
1 answer:
olya-2409 [2.1K]2 years ago
3 0

Answer:

1482.6 J

Explanation:

353 cal * 4.2 J / 1 cal = 1482.6 J

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Is sand an element or a compound?
Romashka-Z-Leto [24]
Neither

its a mixture
7 0
3 years ago
820 g Li2SO4 is dissolved into 2500 mL of solution. What is the molar concentration?
Andreas93 [3]

Molarity is defined as the moles of solute per liter of solution. M=\frac{n}{V}. Where M is molarity, n is the number of moles and V is the volume. First we must find the molar mass of Li_2SO_4 which is 109.98 g/mol

Li_2SO_4= 2 \times Li_{Ar} + S_{Ar} + 4 \times O_{Ar}\\= (2 \times 6.941 + 32.1 + 4 \times 16.0) = 109.98 g/mol

820\ g\ Li_2SO_4 \times \frac{mol}{109.98\ g}= 7.46\ mol\ Li_2SO4

Then we find the molarity using above equation

M= \frac{n}{V} = \frac{7.46 mol}{2500ml} \times\frac{1000ml}{L} = 2.98\ M


6 0
3 years ago
If the 3d and 4s bands overlap in a metal atom, what is the maximum number of electrons for this composite band? express your an
Roman55 [17]

Hey there!

3d band can hold as many as 10 electrons, while 4s can bear as many as two electrons.

The maximum number of electrons for this composite band should be 12 electrons.

Hope that helps!

3 0
3 years ago
All answers must have the correct unit! (g/mL) d= mass/volume, d= masa/volumen
Radda [10]

heh.......... sorry man............... but this was posted over 5 hours ago........ so nobody is gonna see it and you probably dont need the answer anymore..... so errrr..... imma justtttt..... take these points :D

8 0
3 years ago
The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H
Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f\times m

or,

\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}

where,

\Delta T_f = change in freezing point

k_f = freezing point constant  (for benzene} =5.12^0Ckg/mol

m = molality

Putting in the values we get:

0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}

{\text{ Mass of solute in g}}=0.028g

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

4 0
3 years ago
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