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3 years ago

An ice cube absorbs 353 cal of

Chemistry

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

1482.6 J

Explanation:

353 cal * 4.2 J / 1 cal = 1482.6 J

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The model below shows the equation that represents how hydrogen and oxygen combine to form water. In this chemical reaction, the

Effectus [21]

Answer:

true

Explanation:

because they are balance

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2 years ago

2. Heliox is a mixture of gases and is used in medicine to help

yaroslaw [1]

Answer:

people with breathing problems such as severe asthma.

Explanation:

Heliox is a medical treatment for patients with difficulty breathing. The mixture generates less resistance than atmospheric air when passing through the airways of the lungs, and thus requires less effort by a patient to breathe in and out of the lungs.

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3 years ago

The density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 via a combust

bearhunter [10]

<u>The answer is </u><u>9.94 ml.</u>

<h3>What is density?</h3>

Density is a word we use to describe how much space an object or substance takes up (its volume) in relation to the amount of matter in that object or substance (its mass).
Another way to put it is that density is the amount of mass per unit of volume. If an object is heavy and compact, it has a high density.

Given,

The density of ethanol, C2H5OH = 0.789 g/mL

$n (CO_{2} ) = \frac{m}{M} = \frac{15G}{44 g/mol} } = 0.341 mol;$

$n ( C_{2} H_{2} OH) = \frac{n (CO_{2}) }{2} = \frac{0.341}{2} = 0.1705 mol;$

$m (C_{2} H_{2} OH) = 0.1705 mol * 46 g/ mol$ = 7.843 g

$V (C_{2} H_{2} OH ) = \frac{7.843}{0.789} = 9.94 ml.$

Therefore, the answer is 9.94 ml

Learn more about density of ethanol,

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<u>The complete question is -</u>

If the density of ethanol, C2H5OH, is 0.789 g/mL. How many milliliters of ethanol are needed to produce 15.0 g of CO2 according to the following chemical equation?

C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l)

5 0

2 years ago

The diagram below shows changes to the nucleus of an atom.

anzhelika [568]

Answer:

maybe 1 or 3 im not sure

Explanation:

i didn't study it yet sorry for not helping but try asking someone else

8 0

3 years ago

Read 2 more answers

If the number of moles of a gas initially contained in a 2.10 l vessel is doubled, what is the final volume of the gas in liters

Anon25 [30]

Avagadro's law gives the relationship between volume of gas and number of moles of the gas. When the temperature and pressure are constant, volume is directly proportional to number of moles of gas.
$\frac{V1}{n1} = \frac{V2}{n2}$
V -volume and n - number of moles of gas.
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
initial number of moles n1 - N
n2 - 2N as the number of moles are doubled
V1 - initial volume - 2.10 L
V2 - final volume - V
substituting the values in the equation
$\frac{2.10L}{N} \frac{V}{2N}$
V = 4.20 L
final volume is 4.20 L

7 0

3 years ago