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jok3333 [9.3K]
3 years ago
7

The difference of 5 times the cube of x cubed and the quotient of 4 times x and 3

Mathematics
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

I don't know what you are looking for, but I am going with (15x^3 - 4x)/3

Step-by-step explanation:

5x^3 - 4x/3

5x^3/1 - 4x/3

15x^3/3 - 4x/3

(15x^3 - 4x)/3

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A triangle has two sides that measure 4ft. and 3ft. Which could be the measure of the 3rd side?
Aneli [31]
In order to form a triangle, the third side must be at least greater than the difference of the other two sides
4 - 3 = 1 So the third side must be greater than 1 foot and the third side must be less than the sum of the other two sides
4 + 3 = 7 So, the third side must be less than 7

1 < third side < 7




4 0
3 years ago
How is the graph of the parent quadratic function transformed to produce the graph of y=-(2x+6) + 3?
Andrews [41]
I believe it’s B I’m not too sure
3 0
3 years ago
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Help me with my math ASAP!!!!
almond37 [142]

Answer:

f = 78

g = 3.5

Step-by-step explanation:

First we need to find f.

We can use the equation 72 + (f + 30) = 180 to solve for f.

We can then change that equation to 72 + f + 30 = 180, since the Commutative Property of Addition says that you can have any addition in any order.

Now, we can solve the equation.

102 + f = 180\\(102 - 102) + f = 180 - 102\\f = 78

Now that we solved f, we can now solve for g.

Since 25 equals 8g -3, we can solve the equation 8g - 3 = 25.

Here is how you solve it:

8g - 3 = 25\\8g + (-3 + 3) = 25 + 3\\8g = 28\\g = \frac{28}{8}

Since \frac{28}{8} equals 3.5, which is the simplest form, that is the answer.

Hope this helps, and please mark me brainliest! :)

3 0
3 years ago
17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II
maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8   when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y)   =   8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8   when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0
3 years ago
Read 2 more answers
i need help on this problem i know how to do this types of problem but i dont get this problem i need hep thank you
Sever21 [200]

Answer:

B: 72

Step-by-step explanation:

Split the shape into separate rectangles! It will make the problem much easier. You can split it so that you will have a 12 x 3 rectangle and a 6 x 6 rectangle because you subtract 3 from 9 and subtract 6 from 12.

12 x 3 = 36

6 x 6 = 36

36 + 36 = 72

Let me know if you're still confused!

8 0
3 years ago
Read 2 more answers
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