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Colt1911 [192]
3 years ago
12

Com que rapidez estará sendo feito trabalho elétrico num resistor de 10 ohms, percorrido por uma corrente elétrica de 5 A? Qual

a energia gasta no mesmo em 2 horas?
Physics
1 answer:
34kurt3 years ago
7 0

Poder = (resistencia) x (corrente)²

Poder = (10 ohms) x (5 A)²

<em>Poder = 250 watts </em>(250 Joule por segundo)

2 horas = 7,200 segundos

Energia = (250 joule/seg) x (7,200 seg)

<em>Energia = 1,800,000 Joules</em>

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A car starts at 25 m/s and then slows down at 13 m/s in 5 seconds. What is the acceleration of the car? What does the accelerati
jek_recluse [69]

Answer:

a=2.4m/s^2

Explanation:

Use V=vi+at

So, 13=25+a5

13-25=a5

\frac{-12}{5}=a

a=2.4m/s^2

5 0
3 years ago
Rank from most to least, the amount of lift on the following airplane wings: A. Area 1500 m2 with atmospheric pressure differenc
AveGali [126]

Answer:

C) >A)>B)

Explanation:

We know that force per unit area is known as pressure.But we have to understand that this force should be perpendicular to the area.

 P = F/A

P=Pressure

F= Force

A=Area

A)

Given that

ΔP=2.9 N/m²

A=1500 m²

F= ΔP x A

F= 2.9 x 1500

F=4350 N

B)

Given that

ΔP=4.7 N/m²

A=900 m²

F= ΔP x A

F= 4.7 x 900

F= 4230 N

C)

Given that

ΔP=8.8 N/m²

A=500 m²

F= ΔP x A

F= 8.8 x 500

F=4400 N

4400 N > 4350 N > 4230

C) >A)>B)

5 0
3 years ago
It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.
natali 33 [55]

Answer:

<em>The ratio of gravitational force to electrical force is 3.19 x 10^-36 </em>

<em></em>

Explanation:

mass of an alpha particle = 6.64 x 10^{-27} kg

charge on an alpha particle = +2e = +2(1.6 x 10^{-19} C) = 3.2 x 10^{-19} C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = \frac{Gm^{2} }{r^{2} }

where G = gravitational constant = 6.67 x 10^{-11} m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = \frac{6.67*10^{-11}*(6.64*10^{-27} )^{2}  }{d^{2} } = \frac{2.94*10^{-63} }{d^{2} }  Newton

For electrical repulsion:

Electrical force between the particles = \frac{-kQ^{2} }{r^{2} }

where k is the Coulomb's constant = 9.0 x 10^{9} N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = \frac{-9*10^{9}*(3.2*10^{-19} )^{2}  }{d^{2} } = \frac{-9.216*10^{-28} }{d^{2} } Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = \frac{2.94*10^{-63} }{9.216*10^{-28} }

==> <em>3.19 x 10^-36 </em>

8 0
3 years ago
Exam
Sedaia [141]
Out put work
explanation:
3 0
3 years ago
Read 2 more answers
What is the speed of sound at the atmospheric temperature of 30°C?
12345 [234]

The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.


First, we determine how long the parcel will fall using:


s = ut + 1/2 at²


where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.


5.5 = (0)(t) + 1/2 (9.81)(t)²

t = 1.06 seconds



A

4 0
3 years ago
Read 2 more answers
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