Answer:
0.04
Explanation:
Fraction of power converted to sound = 80% = 0.08
Fraction incident upon each eardrum onstage = 0.08/2 = 0.04
Answer:
0.76 rad/s^2
Explanation:
First, we convert the original and final velocity from rev/s to rad/s:


Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:

Now, we just use the formula:


Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration, 
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,



Frictional force is given by :


F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.
<u>Answer</u>
D. 1,500 m/s
<u>Explanation</u>
the wave equation states that,
V = λf
Where V ⇒ Velocity
λ ⇒ wavelength
f ⇒ Frequency
F = 1/T
Where T ⇒ period
F = 1/0.006
= 166.667
∴ V = 9 × 166.667
= 1,500 m/s