What is the specific heat for the aluminum wire?

We showed that the length of the pendulum of period 2.000 seconds on the Earth’s surface was 0.99396 meters. What period would t

Kitty [74]

To solve this problem it is necessary to apply the concepts related to the Period based on gravity and length.

Mathematically this concept can be expressed as

$T= 2\pi \sqrt{\frac{l}{g}}$

Where,

l = Length

g = Gravitational acceleration

First we will find the period that with the characteristics presented can be given on Mars and then we can find the length of the pendulum at the desired time.

The period on Mars with the given length of 0.99396m and the gravity of the moon (approximately $1.62m / s ^ 2)$ will be

$T= 2\pi \sqrt{\frac{l}{g}}$

$T= 2\pi \sqrt{\frac{0.99396}{1.62}}$

$T = 4.921seg$

For the second question posed, it would be to find the length so that the period is 2 seconds, that is:

$T= 2\pi \sqrt{\frac{l}{g}}$

$2= 2\pi \sqrt{\frac{l}{1.62}}$

$l = 0.16414m$

Therefore, we can observe also that the shorter distance would be the period compared to the first result given.

8 0

3 years ago

How long does it take a person at rest to breathe one mole of air if the person breathes 77.0 ml/s of air that is measured at 25

Natali5045456 [20]

<span>320. seconds The ideal gas law is PV = nRT where P = pressure of the gas V = volume of the gas n = number of moles of the gas R = the ideal gas constant T = absolute temperature of the gas. Since we're going to want the volume, solve for V PV = nRT V = nRT/P 755 mmHg converts to 100658.11 Pascals 25 C = 298.15 K Let's calculate nT/P, then we'll multiply by R 1 mol * 298.15 K / 100658.11 Pa = 0.002962007 K mol/Pa The value for R in the most convenient units is 8.3144598 m^3 Pa/(K mol), so 0.002962007 K mol/Pa * 8.3144598 m^3 Pa/(K mol) = 0.024627486 m^3 So 1 mole of air at the specified temperature and pressure has a volume of 24.627 liters. The rest of the problem is now trivial. Just divide by the rate of consumption, so 24.627 l / 0.0770 l/s = 319.8374798 s Rounding the result to 3 significant figures gives 320. seconds.</span>

4 0

3 years ago

Calculate the amount of energy produced in joules by 100- watt light bulb lit for 2.5 hours.

9966 [12]

100/2.5 is 40.
40 is the energy that is being produced

4 0

4 years ago

A rope is wrapped around the rim of a large uniform solid disk of mass 325 kg and radius 3.00 m. The horizontal disk is made to

Naily [24]

Answer:

The angular speed is 0.13 rev/s

Explanation:

From the formula

$\tau = I\alpha$

Where $\tau$ is the torque

$I$ is the moment of inertia

$\alpha$ is the angular acceleration

But, the angular acceleration is given by

$\alpha = \frac{\omega}{t}$

Where $\omega$ is the angular speed

and $t$ is time

Then, we can write that

$\tau = \frac{I\omega}{t}$

Hence,

$\omega = \frac{\tau t}{I}$

Now, to determine the angular speed, we first determine the Torque $\tau$ and the moment of inertia $I$ .

Here, The torque is given by,

$\tau = rF$

Where r is the radius

and F is the force

From the question

r = 3.00 m

F = 195 N

∴ $\tau = 3.00 \times 195$

$\tau = 585$ Nm

For the moment of inertia,

The moment of inertia of the solid disk is given by

$I = \frac{1}{2}MR^{2}$

Where M is the mass and

R is the radius

∴ $I = \frac{1}{2} \times 325 \times (3.00)^{2}$

$I = 1462.5$ kgm²

From the question, time t = 2.05 s.

Putting the values into the equation,

$\omega = \frac{\tau t}{I}$

$\omega = \frac{585 \times 2.05}{1462.5}$

$\omega = 0.82$ rad/s

Now, we will convert from rad/s to rev/s. To do that, we will divide our answer by 2π

0.82 rad/s = 0.82/2π rev/s

= 0.13 rev/s

Hence, the angular speed is 0.13 rev/s,

6 0

3 years ago

What does atomic spectrum mean?

lapo4ka [179]

Answer:

The range of characteristic frequencies of electromagnetic radiation that are readily absorbed and emitted by an atom. The atomic spectrum is an effect of the quantized orbits of electrons around the atom

Additional Facts:

Atomic spectra can also be analyzed to determine the composition of objects
The frequency depends on the difference in energy between the orbitals. Explaining this phenomenon was crucial to the development of quantum mechanics
Occurs due to the fact are quantized at specific levels determined by the atomic number

3 0

3 years ago