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Drupady [299]
3 years ago
6

What requirements do you need for stoichiometry?

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

Explanation:

Balance the equation.

Convert units of a given substance to moles.

Using the mole ratio, calculate the moles of substance yielded by the reaction.

Convert moles of wanted substance to desired units.

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Which sample contains a total of 3.0 x 10^23 molecules?
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Given that 1 mole contains 6.02x10^23 molecules, 3.0x10^23 is just around half a mole. Then we check the number of moles for each choice:

A. This is approximately half a mole, since the molar mass of Br2 is 159.8 g/mol.
B. He has a molar mass around 4 g/mol, so this is 1 mole.
C. H2 has a molar mass of 2.02 g/mol, so this is 2 moles.
D. Li has a molar mass of around 6.97 g/mol, so this is around 2 moles.

Therefore the only choice that fits is A. 80 g of Br2.
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A solid block of wood has a mass of 132.5kg and a
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Answer these questions based on 234.04360 as the atomic mass of thorium-234. The masses for the subatomic particles are given. R
Scilla [17]

How many protons does Thorium have? 90

How many neutrons does Thorium-234 have? 144

Calculate the mass defect for the isotope thorium-234 1.85864 amu

4 0
3 years ago
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Which of these is a covalent compound?
OLga [1]
A. NO2 because the elements are both nonmetals.
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3 years ago
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Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

6 0
3 years ago
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