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mixas84 [53]
1 year ago
11

Write the balanced chemical equation for each of the reactions. Include phases. When aqueous sodium hydroxide is added to a solu

tion containing lead(II) nitrate, a solid precipitate forms.
Chemistry
1 answer:
Kitty [74]1 year ago
6 0

The balanced chemical equation for aqueous sodium hydroxide being added to a solution containing lead(II) nitrate and a solid precipitate being formed is :

2 NaOH (aq) + Pb(NO3)₂ (aq) ⇒ Pb(OH)₂ (s) + 2 NaNO₃ (aq)

A balanced chemical equation is the one in which the number of atoms are equal for every element on both the the reactant side as well as the product side. Their charges should also be the same.

A precipitate is a solid mass of some substance that forms up in a liquid solution due to certain chemical reactions. This solid mass does not dissolve in the liquid solution.

To know more about balanced chemical equation, here

brainly.com/question/8062886

#SPJ4

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How many moles of aluminum are needed to react completely with 1.2 mol of feo
Amanda [17]

Answer:

0.8 mol.

Explanation:

  • The balanced equation for the reaction between Al and FeO is represented as:

<em>2Al + 3FeO → 3Fe + Al₂O₃,</em>

It is clear that 2 mol of Al react with 3 mol of FeO to produce 3 mol of Fe and 1 mol of Al₂O₃.

<em><u>Using cross multiplication:</u></em>

2 mol of Al needs → 3 mol of FeO, from stichiometry.

??? mol of Al needs → 1.2 mol of FeO.

∴<em> The no. of moles of Al are needed to react completely with 1.2 mol of FeO </em>= (2 mol)(1.2 mol)/(3 mol) = <em>0.8 mol.</em>

3 0
3 years ago
To determine the ammonia concentration in a sample of lake water, three samples are prepared. In sample A, 10.0 mL of lake water
Masteriza [31]

Answer:Sample Absorbance (625 nm)  

A 0.536  

B 0.783  

C 0.045  

Therefore, I will use these data to solve your question. If you have other absorbances values, just follow my steps and plug in different numbers.

First, we see 1 mole of NH3 gives 1 mole product.

In B moles of NH3 = moles of NH3 in A + (5.5 x10^-4 x2.5/1000) = 1.375 x10^6 + mA

( mA = moles of NH3 in A) vol of B = 25 = vol of A

now A = el C = eC ( since l = 1cm)

Because, n net absorbance due to complex blank absorbance must be removed.

Here A(A) = 0.536 - 0.045 = 0.491 , A(B) = 0.783 - 0.045 = 0.738  

(you can plug in different numbers in this step)

A2/A1 = C2/C1 , A(B)/A(A) = (1.375x10^-6 +mA)/(mA) = 0.738/0.491

So, mA = 2.733 x 10^-6 = moles of NH3 in A (Lake water)

Hence [NH3] water ( 2.733 x10^-6 ) x 1000/25 = 1.093 x 10^-4 M

Lake water vol = 10 ml out of 25,

Concentration of ammonia in lake water = 2.733 x10^-6 x 1000/10 = 2.733 x 10^-4 M

Then, A = 0.491 = e x 1 x 1.093 x10^-4

e = 4492 M-1cm-1

Explanation:

4 0
3 years ago
The hammer, anvil, and stirrup are all bones found in the ear.
AfilCa [17]

Answer: Hammer, anvil and stirrup are small bones in the ear behind ear drum and before cochlea. These bones helps in transfering the vibrations from ear drum to the cochlea which is further passed to auditory nerve and then to brain

Explanation:

4 0
3 years ago
Find the density.... Mass is 138g and Volume is 100 mL​
solniwko [45]

Answer:

1380 kilogram/cubic meter

p=\frac{m}{v}

=\frac{138g}{100mL}

=1.38

=1380

4 0
3 years ago
Which solution below has the highest concentration of hydroxide ions?a. pH= 3.21b. pH= 7.00c. pH= 7.93d. pH= 12.59e. pH= 9.82
Sloan [31]

Answer:

  • <em>The solution that has the highest concentration of hydroxide ions is </em><u>d. pH = 12.59.</u>

Explanation:

You can solve this question using just some chemical facts:

  1. pH is a measure of acidity or alkalinity: the higher the pH the lower the acidity and the higher the alkalinity.
  2. The higher the concentration of hydroxide ions the lower the acidity or the higher the alkalinity of the solution, this is the higher the pH.

Hence, since you are asked to state the solution with the highest concentration of hydroxide ions, you just pick the highest pH. This is the option d, pH = 12.59.

These mathematical relations are used to find the exact concentrations of hydroxide ions:

  • pH + pOH = 14 ⇒ pOH = 14 - pH

  • pOH = - log [OH⁻] ⇒ [OH^-]=10^{-pOH}

Then, you can follow these calculations:

Solution    pH        pOH                            [OH⁻]

a.               3.21       14 - 3.21 = 10.79        antilogarithm of 10.79 = 1.6 × 10⁻¹¹

b.               7.00      14 - 7.00 = 7.00        antilogarithm of 7.00 = 10⁻⁷

c.                7.93      14 - 7.93 = 6.07        antilogarithm of 6.07 = 8.5 × 10⁻⁷

d.               12.59     14 - 12.59 = 1.41        antilogarithm of 1.41 = 0.039

e.               9.82      14 - 9.82 = 4.18        antilogarithm of 4.18 = 6.6 × 10⁻⁵

From which you see that the highest concentration of hydroxide ions is for pH = 12.59.

5 0
3 years ago
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