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mixas84 [53]
1 year ago
11

Write the balanced chemical equation for each of the reactions. Include phases. When aqueous sodium hydroxide is added to a solu

tion containing lead(II) nitrate, a solid precipitate forms.
Chemistry
1 answer:
Kitty [74]1 year ago
6 0

The balanced chemical equation for aqueous sodium hydroxide being added to a solution containing lead(II) nitrate and a solid precipitate being formed is :

2 NaOH (aq) + Pb(NO3)₂ (aq) ⇒ Pb(OH)₂ (s) + 2 NaNO₃ (aq)

A balanced chemical equation is the one in which the number of atoms are equal for every element on both the the reactant side as well as the product side. Their charges should also be the same.

A precipitate is a solid mass of some substance that forms up in a liquid solution due to certain chemical reactions. This solid mass does not dissolve in the liquid solution.

To know more about balanced chemical equation, here

brainly.com/question/8062886

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If heat energy is transferred from direct contact between a warm object and a cold object, it has been transferred by __________
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If heat energy is transferred from direct contact between a warm object and a cold object, it has been transferred by Convection.

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Use the following image to answer the following questions. A student was performing an experiment using two identical cups made
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2 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
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