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sukhopar [10]
1 year ago
11

An adiabatic throttling valve expands an ideal gas. The internal energy of the ideal gas?

Chemistry
1 answer:
just olya [345]1 year ago
3 0

The internal energy of the ideal gas is zero

The change in internal energy  for an isothermal process is zero.

An ideal gas has no interactions between particles, therefore no intermolecular forces.

pressure change at constant temperature does not change the internal energy.

Adiabatic throttling expansion has less work done and lower heat flow.

That lower the internal energy.

The temperature decreases during the adiabatic expansion

Hence the internal energy of the ideal gas is zero

Learn more about the ideal gas on

brainly.com/question/17136449

#SPJ4

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Two isotopes of hypothetical element X exist with abundances of 30.00% 100X and 70.00% 101X. What is the approximate atomic mass
Rasek [7]

Answer:

C. 100.7 amu

Explanation:

Isotopes of an element are atoms of an element with the same atomic number but different atomic masses. Each atomic mass of an isotope is known as an isotopic mass. An element that exhibits isotope, that is, that have two or more isotopes has a relative atomic mass that is not a whole number.

Relative atomic mass of X is the sum of the products of the relative abundances of each isotope and its isotopic mass.

For Isotope ¹⁰⁰X: 30% × 100 = 30 amu

For Isotope ¹⁰¹X: 70% × 101 = 70.7 amu

Relative atomic mass of X = (30 + 70.7) amu = 100.7 amu

Therefore, the approximate atomic mass of X is 100.7 amu

4 0
2 years ago
A solution containing 0.102 g of an unknown compound dissolved in 100. mL of water has an osmotic pressure of 28.1 mmHg at 20.°C
IrinaVladis [17]

Answer:

MM = 680g / mol

Explanation:

Hello! To calculate the molar mass of the compound (g / mol), I first have to calculate the molarity.

Molarity can be calculated from the osmotic pressure equation.

op = M * R * T

op = osmotic pressure = 28.1mmHg * (1 atm / 760mmHg) = 0.037atm

M = molarity

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T = temperature (K) = 20 ° C + 273.15 = 293.15K

M (mol / L) = op / R * T

M = 0.037atm / ((0.082 (atm * L) / (K * mol)) * 293.15K) = 0.0015mol / L

As I have the volume = 100ml * (1L / 1000ml) = 0.1L

I can calculate the amount of moles

n = M * V = 0.0015 * 0.1 = 0.00015mol

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m = mass

MM = molar mass

MM = m / n = 0.102g / 0.00015mol

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4 0
3 years ago
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aalyn [17]

Answer:

The correct option is B

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