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2 years ago

An adiabatic throttling valve expands an ideal gas. The internal energy of the ideal gas?

Chemistry

1 answer:

just olya [345]2 years ago

3 0

The internal energy of the ideal gas is zero

The change in internal energy for an isothermal process is zero.

An ideal gas has no interactions between particles, therefore no intermolecular forces.

pressure change at constant temperature does not change the internal energy.

Adiabatic throttling expansion has less work done and lower heat flow.

That lower the internal energy.

The temperature decreases during the adiabatic expansion

Hence the internal energy of the ideal gas is zero

Learn more about the ideal gas on

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Balance each of the following redox reactions occurring in acidic aqueous solution.

dmitriy555 [2]

Answer:

Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

Part B : 3Mg(s) + 2Cr³⁺(aq) → 3Mg²⁺(aq) + 2Cr(s).

Part C: 3MnO₄⁻ + 24H⁺ + 5Al → 5Al³⁺ + 3Mn²⁺ + 12H₂O.

Explanation:

Part A : Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s), Express your answer as a chemical equation. Identify all of the phases in your answer.

It is balanced as written: Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

The two half reactions are:

The oxidation reaction: Zn(s) → Zn²⁺(aq) + 2e.

The reduction reaction: Sn²⁺(aq) + 2e → Sn(s).

To obtain the net redox reaction, we add the two-half reactions as the no. of electrons in the two-half reactions is equal.

So, the net chemical equation is:

Zn(s) + Sn²⁺(aq) → Zn²⁺(aq) + Sn(s).

Part B: Mg(s) + Cr³⁺(aq) → Mg²⁺(aq) + Cr(s), Express your answer as a chemical equation. Identify all of the phases in your answer.

To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Mg(s) → Mg²⁺(aq) + 2e.

The reduction reaction: Cr³⁺(aq) + 3e → Cr(s).

To obtain the net redox reaction, we multiply the oxidation reaction by 3 (3Mg(s) → 3Mg²⁺(aq) + 6e) and the reduction reaction by 2 (2Cr³⁺(aq) + 6e → 2Cr(s)) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

3Mg(s) + 2Cr³⁺(aq) → 3Mg²⁺(aq) + 2Cr(s).

Part C : MnO⁴⁻(aq) + Al(s) → Mn²⁺(aq) + Al³⁺(aq), Express your answer as a chemical equation. Identify all of the phases in your answer.

To balance and write the net chemical equation, we should write the two-half reactions:

The two half reactions are:

The oxidation reaction: Al → Al³⁺ + 3e.

The reduction reaction: MnO₄⁻ + 8H⁺ + 5e → Mn²⁺ + 4H₂O.

To obtain the net redox reaction, we multiply the oxidation reaction by 5 (5Al → 5Al³⁺ + 15e) and the reduction reaction by 3 (3MnO₄⁻ + 24H⁺ + 15e → 3Mn²⁺ + 12H₂O) to equalize the no. of electrons in the two-half reactions.

So, the net redox reaction will be:

3MnO₄⁻ + 24H⁺ + 5Al → 5Al³⁺ + 3Mn²⁺ + 12H₂O.

4 0

4 years ago

Indicate the number of unpaired electrons in He. Express your answer as an integer.

Aleonysh [2.5K]

Answer : The number of unpaired electrons in helium is, 0

Explanation :

As we are given that the element is helium. The symbol of helium element is, (He).

The atomic number of helium element is, 2 that means it has 2 number of electrons.

Electronic configuration : It is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom are determined by the electronic configuration.

The electronic configuration of helium element is: $1s^2$

There is no unpaired electrons in helium element.

Hence, the number of unpaired electrons in helium is, 0

3 0

4 years ago

A) saturated B)desaturated C)unsaturated D)supersaturated

Lesechka [4]

Answer:

No Its B Unsaturated becuase the line is slanted

Explanation:

4 0

4 years ago

Be sure to answer all parts.

Over [174]

The dissociation constant is 2.44 mM.

Explanation:

Dissociation constant of any acid or any kind of solutions is the measure of amount dissolved in the solution or separated into different elements. So it is calculated as the ratio of product of concentration of dissociated elements to the concentration of the original compound.

Here the concentration of the acid [HA] = 0.035 M, the pH of the acid is given as 4.67.

$pH=-log[H^{+}]$

$[H^{+}]=e^{-pH} = \frac{1}{e^{pH} } = \frac{1}{e^{4.67} } =\frac{1}{107}$

$[H^{+}]=9.35 \times 10^{-3} M$

Then, $K_{a} =\frac{[H^{+}][A^{-}] }{[HA]} =\frac{(9.35 \times 10^{-3}) ^{2} }{0.035}\\ \\K_{a} = 2497.78 \times 10^{-6}$

Thus, the dissociation constant is 2.44 mM.

3 0

4 years ago

Hey guys!

melamori03 [73]

Pajamas

Out fit for each day + 2 extra

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Light hoodie

Bathing suit + cover up

Underwear

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Razor

Medicine (pain meds, etc.)

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Retainer (if you have 1)

Tooth brush + toothpaste

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Phone charger

Computer + computer charger

Camera + camera charger

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Blow dryer

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Have music + shows/ movies downloaded

Hope this helps you take off anything you don't want or anything you don't need

7 0

3 years ago